Question

如何找到修复SP的解决方案，当我从php运行时，我得到Error 102 severity 15 state 1 PHP：

$stmt = mssql_init('DBO.TEST_sp_SET_Claim Status');
mssql_bind($stmt, '@ClaimID', $claimID, SQLINT4);
mssql_bind($stmt, '@Status', $status, SQLINT4);
mssql_bind($stmt, '@UserID', $userID, SQLINT4);
$result = mssql_execute($stmt);

SP：

  @ClaimID INT,
  @Status INT,
  @UserID INT
AS
BEGIN
  SET NOCOUNT ON;
  --Start : Update claim Status.
  UPDATE    DBO.Payment
      SET StatusID = @Status, 
        ClosedBy = CASE 
                WHEN @Status = 2 THEN @UserID
                WHEN @Status = 13 THEN @UserID
                WHEN @Status = 14 THEN @UserID
                WHEN @Status = 16 THEN @UserID
                ELSE NULL 
              END ,
        UserID = @UserID, 
        DateClosed = CASE 
                WHEN @Status = 2 THEN GETDATE()
                WHEN @Status = 13 THEN GETDATE()
                WHEN @Status = 14 THEN GETDATE()
                WHEN @Status = 16 THEN GETDATE()
                ELSE NULL 
              END
  FROM  DBO.ClaimHeader P_CH
      INNER JOIN DBO.Payment P_PI ON P_CH.ClientClaimID = P_PI.ClientClaimID
  WHERE P_CH.ClientClaimID  = @ClaimID              
  --End

END

在SQL Server Profiler中我得到

Exception           Error 102 severity 15 state 1
SQL:BatchStarting   EXEC DBO.TEST_sp_SET_Claim Status @ClaimID=20,@Status=4,@UserID=22
SQL:BatchCompleted  EXEC DBO.TEST_sp_SET_Claim Status @ClaimID=20,@Status=4,@UserID=22

当我直接在sql中运行时，它工作正常

DECLARE @return_value int

EXEC    @return_value = [dbo].[TEST_sp_SET_Claim Status]
    @ClaimID = 20,
    @Status = 4,
    @UserID = 22

SELECT  'Return Value' = @return_value

当我直接从php运行查询时，它的工作原理很像

     $query="
  DECLARE @Status INT, @UserID INT, @ClaimID INT
  SET @Status=$status
  SET @UserID = $userID
  SET @ClaimID = $claimID
  UPDATE    DBO.Payment
      SET StatusID = @Status, 
        ClosedBy = CASE 
                WHEN @Status = 2 THEN @UserID
                WHEN @Status = 13 THEN @UserID
                WHEN @Status = 14 THEN @UserID
                WHEN @Status = 16 THEN @UserID
                ELSE NULL 
              END ,
        UserID = @UserID, 
        DateClosed = CASE 
                WHEN @Status = 2 THEN GETDATE()
                WHEN @Status = 13 THEN GETDATE()
                WHEN @Status = 14 THEN GETDATE()
                WHEN @Status = 16 THEN GETDATE()
                ELSE NULL 
              END
  FROM  DBO.ClaimHeader P_CH
      INNER JOIN DBO.Payment P_PI ON P_CH.ClientClaimID = P_PI.ClientClaimID
  WHERE P_CH.ClientClaimID  = @ClaimID  
       ";
 $result=mssql_query($query);

我唯一能想到的是名称TEST_sp_SET_Claim Status中的空格，但是这个Sp也被其他应用程序使用，它运行正常，我无法改变......可能是另一回事？

Answer 1

问题是SP名称DBO.TEST_sp_SET_Claim Status，状态之前有一个空格。我修复了方括号[]

中的SP名称

$stmt = mssql_init('[DBO].[TEST_sp_SET_Claim Status]');

建议使用方括号来避免这种问题。

如果列名或Sp名称包含空格或与保留字冲突

List of Reserved Keywords in SQL-SERVER

如何调试错误102严重性15状态1

1 个答案: