的修改

Question

你好我正在拉我的头发试图找出如何在用户从下拉菜单中选择“日期”之后用数据库中的信息填充文本框。

我的下拉菜单当前正由巡视的departure_date填充，我希望与该日期相关的所有其他信息都显示在页面的文本框中。

这是我正在处理的项目，我们当前的服务器不幸地支持pdo。

这让我头晕目眩，我无法思考我应该如何实现这一目标。在互联网上搜索没有给我任何有用的信息。

这是我的选择框和文本框的html代码。

<div>

  <label><strong>Search Tours</strong></label>
<form>
  <p>
    <select name="lst_tour">
      <option value="">Select a Tour:</option>
      <?php 

foreach ( $results as $option ) : ?>
      <option value="<?php

          echo $option->departure_date; ?>"><?php echo $option->departure_date; ?>    </option>
      <?php endforeach; ?>
    </select>
  </p>
  <p><strong>List of Tour Details</strong></p>


        <input name="txt_tourname" type="text" id="txt_tourname" readonly="readonly"     value = <?php echo $ltour_name ?> />
      </label></td>

        <input name="txt_departuredate" type="text" id="txt_departuredate"  readonly="readonly" />
      </label>


        <input name="txt_tourdetails" type="text" id="txt_tourdetails"     readonly="readonly" />
      </label>

这是我的php连接代码

     <?php
session_start();

        $server = "server";
        $schema = "schema";
        $uid = "name";
        $pwd = "pass";

    $tour_name =$_POST["txt_tourname"];
    $departure_date =$_POST["txt_departuredate"];
    $tour_details =$_POST["txt_tourdetails"];
    $no_of_volunteers =$_POST["txt_noofvolunteers"];


mysql_connect($server , $uid , $pwd) or die ("server not found");
mysql_select_db($schema) or die ("Database not found");

     $sql = "SELECT * FROM tour";
     $query = mysql_query($sql);
     while ( $results[] = mysql_fetch_object ( $query ) );
     array_pop ( $results );
?>

任何帮助都会很棒

Answer 1

好的，这个问题被提出并得到了很多回答，而且大多数问题都存在概念问题。我将在部分内容进行解释，之后我会发布一个干净的代码重写，包括一个javascript文件，供您潜入并学习

你想要做的事情背后的想法涉及某些看起来很可能是静态html页面的行为
Javascript 为您原本不用的html添加行为，允许您触发事件并生成回复
Ajax 的诞生是出于集体必需，在用户没有离开页面时能够与服务器通信。它允许我们在场景后面发出请求（异步）并带回信息
将行为与异步请求相结合的力量是当今富互联网应用程序的基础（简称RIA？）

好的，不要以表面价值为依据，对它进行一些研究，你会发现它的潜力。在此期间，我将创建一个你想要的样本的模型，并且我会尽快回来。请注意其他答案，^^周围有很多知识渊博的人。

的修改

html表单

<form method="somemethod" action="somescript.php">
  <select name="lst_tour" id="lst_tour">
    <option value="">Select a Tour:</option>
    <?php foreach ( $results as $option ) {
      ?><option value="<?php echo $option->departure_date; ?>"><?php echo $option->departure_date; ?></option><?php
    } ?></select>
  <!-- these will be "magically" populated, they conveniently have ids ^^ -->
  <input name="txt_tourname" type="text" id="txt_tourname" readonly="readonly" />
  <input name="txt_departuredate" type="text" id="txt_departuredate" readonly="readonly" />
  <input name="txt_tourdetails" type="text" id="txt_tourdetails" readonly="readonly" />
</form>

的javascript

很多编辑和重写。这是一个带有大量alerts的嘈杂脚本，所以请耐心等待，并在您不再需要时依次开始删除警报。 注意：选择标记有一个ID ，我用它来查找它并附加事件处理程序

(function(){
  var
    // the php script that's taking care of business
    url = 'http://path/to/handling/ajaxscript.php',
    select,
    // assume these are the ids of the fields to populate
    //  AND assume they are the keys of the array thats comming from the server
    inputs = ['txt_tourname','txt_departuredate','txt_tourdetails'],
    // the XMLHttpRequest, I'm not recycling it but, oh well
    xhr,
    // the onReadyStateChange handler function, it needs access to xhr
    xhrRSC,
    // event handler, called for <select>."onChange"
    onChooseDate,
    // response handler that will be executed once the xhrRSC deems it ready
    populateData,
    // convenient event handlers
    onLoad, onUnload;
  xhrRSC = function () {
    if (xhr && xhr.readyState !== 4) {return;}
    alert('the server response has completed. Now continue with the population');
    populateData(JSON.parse(xhr.responseText));
    xhr = null;
  };
  onChooseDate = function () {
    var date = select.options[select.selectedIndex].value;
    alert('I have been changed. Did I select the right date: '+date
      +'. Now we send some info to the server');
    // AJAX: make xhr
    xhr = new XMLHttpRequest();
    // AJAX: setup handler
    xhr.onreadystatechange = xhrRSC;
    // AJAX: open channel
    xhr.open('get',url+'?ajax=1&date='+date,true);
    // AJAX: send data (if method post)
    xhr.send(null);
    // if we had jQuery, we could condense all this into one line
    // $.post(url,{ajax:1,date:date},populateData,'json');
  };
  populateData = function (json) {
    // we have the content from the server. Now json decode it
    alert('json data => '+json.toSource());
    // foreach input id execute function
    inputs.forEach(function(v){
      // set the value of each input to the data sent by the server
      alert('setting input "'+v+'" to "'+json[v]+'"');
      document.getElementById(v).value = json[v];
    });
  };
  onLoad = function () {
    alert('page has loaded');
    // assume the <select> tag has an id of "lst_tour", just as it's name
    select = document.getElementById('lst_tour');
    // the "change" event is fired when the user changes the selected <option>
    select.addEventListener('change',onChooseDate,false);
  };
  onUnload = function () {
    select.removeEventListener('change',onChooseDate,false);
    select = null;
  };
  window.addEventListener('load',onLoad,false);
  window.addEventListener('unload',onUnload,false);
}());

ajax脚本，php处理程序

<?php
// this file has $_GET populated with 'ajax' => '1' and 'date' => 'what the user chose'
if (!isset($_GET['ajax'])) die('this is not how its supposed to work');
// we must protect the output
ob_start();
// your initializers
// your logic: it should make the selection, then populate the array to be JSON encoded

$response = array(
  'txt_tourname' => $txt_tourname,
  'txt_departuredate' => $txt_departuredate,
  'txt_tourdetails' => $txt_tourdetails
);
// you may want to log this for debugging
// server output has been protected
ob_end_clean();
header('Content-Type: text/json');
echo json_encode($response);
// the client has what he wanted
exit;

在那里，它没有经过测试，而且它是一个满满的，但经过仔细审查，你将学到很多东西。另请阅读 Crockford ，并考虑使用jQuery的好处，javascript可能不那么复杂，jQuery更高效

使用带有数据库信息的下拉菜单填充文本框

1 个答案:

的修改

html表单

的javascript

ajax脚本，php处理程序