MySQL Select Statement无效

Question

我正在尝试创建一个要在视图中使用的select语句。目标是创建一个显示办公室描述，聚会描述，候选人姓名和任务指示的视图。我有下表是我的数据库：

SELECT `OFFICE DESCRIPTION`,
       `PARTY DESCRIPTION`,
       `CANDIDATE NAME`,
       `INCUMBANT INDICATOR`   
FROM   OFFICE,PARTY,CANDIDATE 
WHERE  CANDIDATE.`OFFICE CODE`= OFFICE.`OFFICE CODE` 
       AND CANDIDATE.`CANDIDATE ID`=`PARTY CANDIDATE`.`CANDIDATE ID` 
       AND `PARTY CANDIDATE`.`PARTY CODE`=PARTY.`PARTY CODE`;

错误：

#1054 - Unknown column 'PARTY CANDIDATE.CANDIDATE ID' in 'where clause' 

我已经验证了此SQL语句确实存在的所有列，但由于某种原因，它会一直返回PARTY CANDIDAT.CANDIDATE ID不存在的错误。任何帮助，将不胜感激。让我知道你是否需要我更多的内容，包括表格定义和布局。

Answer 1

1. 您需要用反引号括起您的字段名称

2. 您正在从FROM列表中找到派对候选人

   SELECT `OFFICE DESCRIPTION`,`PARTY DESCRIPTION`,`CANDIDATE NAME`,`INCUMBANT INDICATOR` 
   FROM OFFICE,PARTY,CANDIDATE,`PARTY CANDIDATE` 
   WHERE CANDIDATE.`OFFICE CODE`=OFFICE.`OFFICE CODE` 
       AND CANDIDATE.`CANDIDATE ID`=`PARTY CANDIDATE`.`CANDIDATE ID` 
       AND `PARTY CANDIDATE`.`PARTY CODE`=PARTY.`PARTY CODE`;
   

Answer 2

我认为问题出在您的FROM和WHERE条款中。

FROM OFFICE, 'PARTY CANDIDATE', CANDIDATE

WHERE子句应该像

CANDIDATE.'CANDIDATE ID' = 'PARTY CANDIDATE'.'CANDIDATE ID'

Answer 3

解决方案是使用@ justin-kiang辅助的以下SQL代码，并包含distinct函数。

SELECT DISTINCT  `OFFICE DESCRIPTION` ,  `PARTY DESCRIPTION` ,  `CANDIDATE NAME` ,  `INCUMBANT INDICATOR` 
FROM OFFICE, PARTY, CANDIDATE,  `PARTY CANDIDATE` 
WHERE CANDIDATE.`OFFICE CODE` = OFFICE.`OFFICE CODE` 
AND CANDIDATE.`CANDIDATE ID` =  `PARTY CANDIDATE`.`CANDIDATE ID` 
AND  `PARTY CANDIDATE`.`PARTY CODE` = PARTY.`PARTY CODE` 
LIMIT 0 , 30;

Answer 4

试试这个：

SELECT OFFICE.`OFFICE DESCRIPTION`,PARTY.`PARTY DESCRIPTION`,CANDIDATE.`CANDIDATE NAME`,`INCUMBANT INDICATOR` FROM OFFICE,PARTY,CANDIDATE WHERE CANDIDATE.`OFFICE   CODE`=OFFICE.`OFFICE CODE` AND CANDIDATE.`CANDIDATE ID`=`PARTY CANDIDATE`.`CANDIDATE ID` AND     `PARTY CANDIDATE`.`PARTY CODE`=PARTY.`PARTY CODE`;