Question

表I如下

Acc_id | Name   |  Status    | value
----------------------------------------
  101  |  com   |  Active    |  1
  202  |  net   |  Active    |  2
  202  |  net   |  New       |  3
  303  |  com   |  Active    |  1 
  303  |  com   |  New       |  4
  303  |  com   |  Inactive  |  2
  404  |  org   |  Active    |  5
  404  |  org   |  Inactive  |  6
  505  |  gov   |  New       |  2
  505  |  gov   |  Active    |  3

以下代码

   SELECT
     t1.*
   FROM table1 AS t1
   INNER JOIN
  (
    SELECT Acc_id
    FROM table1
    WHERE status IN('Active', 'New')
    GROUP BY Acc_id
    HAVING COUNT(DISTINCT status) = 2
  ) AS t2 ON t1.Acc_id = t2.Acc_id 
    WHERE t1.status IN('Active', 'New');

提供下表

Acc_id | Name   |  Status    | value
----------------------------------------
  202  |  net   |  Active    |  2
  202  |  net   |  New       |  3
  303  |  com   |  Active    |  1 
  303  |  com   |  New       |  4
  505  |  gov   |  New       |  2
  505  |  gov   |  Active    |  3

正如您在上面看到的来自“Acc_id”列的相同ID，其中列“状态”仅选择了“新建”和“活动”

另外，我还想在结果下添加一行。该行应包含一个新的“状态”“现有”，而“值”将是（状态“活动的值” - 状态“新值”）的结果，另一个应该保持不变。

例如：从上面的结果

| ACC_ID | NAME | STATUS  | VALUE |
|--------|------|-------- |-------|
|    202 |  net | Active  |     2 |
|    202 |  net |    New  |     3 |
|    202 |  net | Existing|    -1 |
|    303 |  com | Active  |     1 |
|    303 |  com |    New  |     4 |
|    303 |  com | Existing|    -3 |
|    505 |  gov |    New  |     2 |
|    505 |  gov | Active  |     3 |
|    505 |  gov | Existing|     1 |

Answer 1

您不需要当前查询的复杂性

SELECT active.acc_id,
  active.acc_name,
  'Existing',
  active.value - new.value
INTO table1
FROM (SELECT * FROM table1 WHERE status = 'Active') active
  JOIN (SELECT * FROM table1 WHERE status = 'New') new
    ON active.acc_id = new.acc_id

在表中插入一行，其中计算取决于以前的行

1 个答案: