Question

我有一个由100条记录组成的文本文件，例如

fname,lname,subj1,marks1,subj2,marks2,subj3,marks3.

我需要在python中提取并打印lname和marks1 + marks2 + marks3。我该怎么做？
我是python的初学者。

请帮忙

当我使用split时，我收到错误

TypeError：无法隐式地将'type'对象转换为str。

代码是

import sys
file_name = sys.argv[1]
file = open(file_name, 'r')


for line in file:
    fname = str.split(str=",", num=line.count(str))
    print fname

Answer 1

注意：它不是经过测试的代码。但它试图解决你的问题。请试一试

import csv
with open(file_name, 'rb') as csvfile:
    marksReader = csv.reader(csvfile)
    for row in marksReader:
        if len(row) < 8:  # 8 is the number of columns in your file.
            # row has some missing columns or empty
            continue

        # Unpack columns of row; you can also do like fname = row[0] and lname = row[1] and so on ...
        (fname,lname,subj1,marks1,subj2,marks2,subj3,marks3) = *row

        # you can use float in place of int if marks contains decimals
        totalMarks = int(marks1) + int(marks2) + int(marks3)

        print '%s %s scored: %s'%(fname, lname, totalMarks)

    print 'End.'

Answer 2

如果你想这样做，你就近了。这是你在尝试的吗？

file = open(file_name, 'r')

for line in file.readlines():
    fname = line.rstrip().split(',') #using rstrip to remove the \n
    print fname

Answer 3

"""
sample file content
poohpool@signet.com; meixin_kok@hotmail.com; ngai_nicole@hotmail.com; isabelle_gal@hotmail.com; michelle-878@hotmail.com; 
valerietan98@gmail.com; remuskan@hotmail.com; genevieve.goh@hotmail.com; poonzheng5798@yahoo.com; burgergirl96@hotmail.com;
 insyirah_powergals@hotmail.com; little_princess-angel@hotmail.com; ifah_duff@hotmail.com; tweety_butt@hotmail.com; 
 choco_ela@hotmail.com; princessdyanah@hotmail.com;
"""

import pandas as pd

file = open('emaildump.txt', 'r')

for line in file.readlines():
    fname = line.split(';') #using split to form a list
#print(fname)

df1 = pd.DataFrame(fname,columns=['Email'])
print(df1)

在python中从文本文件中读取逗号分隔值

3 个答案: