Question

我想重命名文件夹中的所有文件。每个文件名将从“whateverName.whateverExt”更改为“namepre + i.whateverExt”。例如从“xxxxx.jpg”到“namepre1.jpg”

我尝试从（Rename files in sub directories）修改代码，但失败了......

import os

target_dir = "/Users/usename/dirctectory/"

for path, dirs, files in os.walk(target_dir):
    for i in range(len(files)):
        filename, ext = os.path.splitext(files[i])
        newname_pre = 'newname_pre'
        new_file = newname_pre + str(i) + ext

        old_filepath = os.path.join(path, file)
        new_filepath = os.path.join(path, new_file)
        os.rename(old_filepath, new_filepath)

有人能帮助我吗？ THX !!!

Answer 1

可能你在命名一些变量时犯了一些错误，试试这个：

import os

target_dir = "/Users/usename/dirctectory/"
newname_tmpl = 'newname_pre{0}{1}'

for path, dirs, files in os.walk(target_dir):
    for i, file in enumerate(files):
        filename, ext = os.path.splitext(file)
        new_file = newname_tmpl.format(i, ext)
        old_filepath = os.path.join(path, file)
        new_filepath = os.path.join(path, new_file)
        os.rename(old_filepath, new_filepath)

Answer 2

试试这个版本：

import os

target_dir = "/Users/usename/dirctectory/"

for path, dirs, files in os.walk(target_dir):
    for i in range(len(files)):
        filename, ext = os.path.splitext(files[i])
        newname_pre = 'newname_pre'
        new_file = newname_pre + str(i) + ext

        old_filepath = os.path.join(path, files[i]) # here was the problem
        new_filepath = os.path.join(path, new_file)
        os.rename(old_filepath, new_filepath)

Answer 3

你应该更新这个问题，说明你运行它时会得到什么输出。此外，尝试在每次迭代时打印出new_file的值，以查看是否获得了正确的文件路径。我的猜测是这一行：

new_file = newname_pre + str(i) + ext

......应该这样说：

new_file = newname_pre + str(i) + '.' + ext

......或者，用稍微更多的Pythonic语法：

new_file = "%s%i.%s" % (newname_pre, i, ext)

使用索引重命名文件名

3 个答案: