Question

我正在构建一个简单的朋友/好友系统，当有人试图搜索新朋友时，我想显示部分隐藏的电子邮件地址，以便了解用户可能是谁，而不会泄露实际细节

所以我希望abcdlkjlkjk@hotmail.com成为abcdl******@hotmail.com。

作为测试，我写道：

<?php
$email = "abcdlkjlkjk@hotmail.com";

$em = explode("@",$email);
$name = $em[0];
$len = strlen($name);
$showLen = floor($len/2);
$str_arr = str_split($name);
for($ii=$showLen;$ii<$len;$ii++){
    $str_arr[$ii] = '*';
}
$em[0] = implode('',$str_arr); 
$new_name = implode('@',$em);
echo $new_name;

这有效，但我想知道是否有更简单/更短的方法来应用相同的逻辑？像正则表达式可能？

Answer 1

这里有一些快速的事情：

function obfuscate_email($email)
{
    $em   = explode("@",$email);
    $name = implode(array_slice($em, 0, count($em)-1), '@');
    $len  = floor(strlen($name)/2);

    return substr($name,0, $len) . str_repeat('*', $len) . "@" . end($em);   
}

// to see in action:
$emails = ['"Abc\@def"@iana.org', 'abcdlkjlkjk@hotmail.com'];

foreach ($emails as $email) 
{
    echo obfuscate_email($email) . "\n";
}

回波：

"Abc\*****@iana.org
abcdl*****@hotmail.com

使用substr()和str_repeat()

Answer 2

这是我的替代解决方案。

我不会使用确切数量的掩码字符来匹配电子邮件的原始长度，而是出于隐私原因使用固定长度掩码。我还会设置允许的最大字符数，以及从不显示超过一半的电子邮件。我还会屏蔽所有小于最小长度的电子邮件。

考虑到这些规则，这是我的带有可选参数的函数：

function maskEmail($email, $minLength = 3, $maxLength = 10, $mask = "***") {
    $atPos = strrpos($email, "@");
    $name = substr($email, 0, $atPos);
    $len = strlen($name);
    $domain = substr($email, $atPos);

    if (($len / 2) < $maxLength) $maxLength = ($len / 2);

    $shortenedEmail = (($len > $minLength) ? substr($name, 0, $maxLength) : "");
    return  "{$shortenedEmail}{$mask}{$domain}";
}

试验：

$email = "";
$tests = [];
for ($i=0; $i < 22; $i++) {
    $email .= chr(97 + $i);

    $tests[] = $email . " -> " . maskEmail("{$email}@example.com");
}
print_r($tests);

结果：

Array
(
    [0] => a -> ***@example.com
    [1] => ab -> ***@example.com
    [2] => abc -> ***@example.com
    [3] => abcd -> ab***@example.com
    [4] => abcde -> ab***@example.com
    [5] => abcdef -> abc***@example.com
    [6] => abcdefg -> abc***@example.com
    [7] => abcdefgh -> abcd***@example.com
    [8] => abcdefghi -> abcd***@example.com
    [9] => abcdefghij -> abcde***@example.com
    [10] => abcdefghijk -> abcde***@example.com
    [11] => abcdefghijkl -> abcdef***@example.com
    [12] => abcdefghijklm -> abcdef***@example.com
    [13] => abcdefghijklmn -> abcdefg***@example.com
    [14] => abcdefghijklmno -> abcdefg***@example.com
    [15] => abcdefghijklmnop -> abcdefgh***@example.com
    [16] => abcdefghijklmnopq -> abcdefgh***@example.com
    [17] => abcdefghijklmnopqr -> abcdefghi***@example.com
    [18] => abcdefghijklmnopqrs -> abcdefghi***@example.com
    [19] => abcdefghijklmnopqrst -> abcdefghij***@example.com
    [20] => abcdefghijklmnopqrstu -> abcdefghij***@example.com
    [21] => abcdefghijklmnopqrstuv -> abcdefghij***@example.com
)

Answer 3

我创建了一个可以帮助某人的功能

    function hideEmail($email)
{
    $mail_parts = explode("@", $email);
    $length = strlen($mail_parts[0]);
    $show = floor($length/2);
    $hide = $length - $show;
    $replace = str_repeat("*", $hide);

    return substr_replace ( $mail_parts[0] , $replace , $show, $hide ) . "@" . substr_replace($mail_parts[1], "**", 0, 2);
}

hideEmail("name@example.com"); // output: na**@**ample.com
hideEmail("something@example.com"); // output: some*****@**ample.com

您可以根据需要自定义..这样的事情（如果长度为4或更少只显示第一个）

    function hideEmail($email) {
    $mail_parts = explode("@", $email);
    $length = strlen($mail_parts[0]);

    if($length <= 4 & $length > 1)
    {
        $show = 1;
        }else{
        $show = floor($length/2);       
    }

    $hide = $length - $show;
    $replace = str_repeat("*", $hide);

    return substr_replace ( $mail_parts[0] , $replace , $show, $hide ) . "@" . substr_replace($mail_parts[1], "**", 0, 2);  
}

hideEmail("name@example.com"); // output: n***@**ample.com
hideEmail("something@example.com"); // output: some*****@**ample.com

Answer 4

我用这个：

 function secret_mail($email)
{

$prop=2;
    $domain = substr(strrchr($email, "@"), 1);
    $mailname=str_replace($domain,'',$email);
    $name_l=strlen($mailname);
    $domain_l=strlen($domain);
        for($i=0;$i<=$name_l/$prop-1;$i++)
        {
        $start.='x';
        }

        for($i=0;$i<=$domain_l/$prop-1;$i++)
        {
        $end.='x';
        }

    return substr_replace($mailname, $start, 2, $name_l/$prop).substr_replace($domain, $end, 2, $domain_l/$prop);
}

输出如下内容： cyxxxxxone @ gmxxxxcom

Answer 5

也许这不是你想要的，但我会这样做：

<?php

    /*

    Here's the logic:

    We want to show X numbers.
    If length of STR is less than X, hide all.
    Else replace the rest with *.

    */

function mask($str, $first, $last) {
    $len = strlen($str);
    $toShow = $first + $last;
    return substr($str, 0, $len <= $toShow ? 0 : $first).str_repeat("*", $len - ($len <= $toShow ? 0 : $toShow)).substr($str, $len - $last, $len <= $toShow ? 0 : $last);
}

function mask_email($email) {
    $mail_parts = explode("@", $email);
    $domain_parts = explode('.', $mail_parts[1]);

    $mail_parts[0] = mask($mail_parts[0], 2, 1); // show first 2 letters and last 1 letter
    $domain_parts[0] = mask($domain_parts[0], 2, 1); // same here
    $mail_parts[1] = implode('.', $domain_parts);

    return implode("@", $mail_parts);
}

$emails = array(
    'a@a.com',
    'ab@aa.com',
    'abc@aaa.com',
    'abcd@aaaa.com',
    'abcde@aaaaa.com',
    'abcdef@aaaaaa.com',
    'abcdefg@aaaaaaa.com',
    'abcdefgh@aaaaaaaa.com',
    'abcdefghi@aaaaaaaaa.com'
);

foreach ($emails as $email){
    echo '<b>'.$email.'</b><br>'.mask_email($email).'<br><hr>';
}

结果：

a@a.com
*@*.com

ab@aa.com
**@**.com

abc@aaa.com
***@***.com

abcd@aaaa.com
ab*d@aa*a.com

abcde@aaaaa.com
ab**e@aa**a.com

abcdef@aaaaaa.com
ab***f@aa***a.com

abcdefg@aaaaaaa.com
ab****g@aa****a.com

abcdefgh@aaaaaaaa.com
ab*****h@aa*****a.com

abcdefghi@aaaaaaaaa.com
ab******i@aa******a.com

Answer 6

例如：

substr($email, 0, 3).'****'.substr($email, strpos($email, "@"));

这会给你类似的东西：

abc****@hotmail.com

Answer 7

有时也可以显示最后一个字符。

ABCDEFZ@gmail.com成为甲***** Z@gmail.com

我建议你保持简单。也许这样的事情很简单 https://github.com/fedmich/PHP_Codes/blob/master/mask_email.php

使用电子邮件显示前3个字符，然后显示@符号前面的最后一个字符

function mask_email( $email ) {
    /*
    Author: Fed
    Simple way of masking emails
    */

    $char_shown = 3;

    $mail_parts = explode("@", $email);
    $username = $mail_parts[0];
    $len = strlen( $username );

    if( $len <= $char_shown ){
        return implode("@", $mail_parts );  
    }

    //Logic: show asterisk in middle, but also show the last character before @
    $mail_parts[0] = substr( $username, 0 , $char_shown )
        . str_repeat("*", $len - $char_shown - 1 )
        . substr( $username, $len - $char_shown + 2 , 1  )
        ;

    return implode("@", $mail_parts );
}

Answer 8

试试这个功能。这适用于有效的电子邮件，例如"Abc\@def"@iana.org。

function hideEmail($email){
    $prefix = substr($email, 0, strrpos($email, '@'));
    $suffix = substr($email, strripos($email, '@'));
    $len  = floor(strlen($prefix)/2);

    return substr($prefix, 0, $len) . str_repeat('*', $len) . $suffix;
}

echo hideEmail('abcdljtrsjtrsjlkjk@hotmail.com');
echo hideEmail('"abc\@def"@iana.org');

返回

abcdljtrs*********@hotmail.com
"abc\*****@iana.org

Answer 9

我有一个功能

function hide_email($email){
$final_str = '';
$string = explode('@', $email);
$leftlength = strlen($string[0]);
$string2 = explode('.', $string[1]);
$string2len = strlen($string2[0]);
$leftlength_new = $leftlength-1;
$first_letter = substr($string[0], 0,1);
$stars = '';
$stars2 = '';
for ($i=0; $i < $leftlength_new; $i++) { 
    $stars .= '*';
}
for ($i=0; $i < $string2len; $i++) { 
    $stars2 .= '*';
}
$stars;
return $final_str .= $first_letter.$stars.'@'.$stars2.'.'.$string2[1];

}

echo hide_email（＆＃39; Hello@PHP.com'）;

Answer 10

如果在@之前有1个字符，则存在问题。我已修复了以下功能。

function obfuscate_email($email)

{  

   $em   = explode("@",$email);
   if(strlen($em[0])==1){
       return   '*'.'@'.$em[1];
   }
   $name = implode(array_slice($em, 0, count($em)-1), '@');
   $len  = floor(strlen($name)/2);
   return substr($name,0, $len) . str_repeat('*', $len) . "@" . end($em);

}

Answer 11

虽然这是一个老线程＆amp;已经有很多答案了。我也想分享我自己的代码片段。

检查它是否是有效的电子邮件。检查和检查多少字符？显示。应该使用什么字符进行审查。

function get_censored_email($email, $show_chars = 3, $censor_char = '*') {
if (filter_var($email, FILTER_VALIDATE_EMAIL)) {

    $char_length = strlen($email);
    $censor_count = $char_length - $show_chars;

    $return_email = substr($email, 0, $show_chars);
    $return_email .= str_repeat("*", $censor_count);

    return $return_email;
}

}

$email = 'noman.ibrahim115@gmail.com';
echo get_censored_email($email, 3, '*'); // returns nom***********************

Answer 12

你也可以尝试这个......

<?php 
$email = "abcdlkjlkjk@hotmail.com";
$resultmob = substr($email,0,5);
$resultmob .= "**********";
$resultmob .= substr($email,strpos($email, "@"));
echo $resultmob;
?>

答案： -

abcdl******@hotmail.com

Answer 13

我正在使用上面的femich答案，并对我的

进行了一些调整

function mask_email($email, $char_shown_front = 1, $char_shown_back = 1)
{
    $mail_parts = explode('@', $email);
    $username = $mail_parts[0];
    $len = strlen($username);

    if ($len < $char_shown_front or $len < $char_shown_back) {
        return implode('@', $mail_parts);
    }

    //Logic: show asterisk in middle, but also show the last character before @
    $mail_parts[0] = substr($username, 0, $char_shown_front)
        . str_repeat('*', $len - $char_shown_front - $char_shown_back)
        . substr($username, $len - $char_shown_back, $char_shown_back);

    return implode('@', $mail_parts);
}

test123@gmail.com-> t ***** 3@gmail.com

您可以传入字符数以显示在正面和背面

Answer 14

这里是只有两行的版本（如果您删除功能内容）。

<?php
function censor_email($str,$amount=2, $char='*') {
    list($local, $domain)=explode("@",$str);
    return substr($local,0,$amount).str_repeat($char,strlen($local)-$amount)."@".$domain;
}
?>

Answer 15

function maskEmail($email) {
    preg_match('/^.?(.*)?.@.+$/', $email, $matches);
    return str_replace($matches[1], str_repeat('*', strlen($matches[1])), $email);
}

echo maskEmail('abcdefgh@example.com')
echo maskEmail('abh@example.com')
echo maskEmail('ah@example.com')
echo maskEmail('a@example.com')

返回

a******h@example.com
a*h@example.com
ah@example.com
a@example.com

Answer 16

另一个已经受到广泛分享的答案影响的变体。

这有两个主要的额外好处：

它将第一个字符保留在已定义的定界符之后，使其在保持隐私的同时更具可读性。
它适用于域名较长的域名，例如.org.uk和.com.au

示例：firstname.lastname@example.co.uk成为f********.l*******@e*****.c*.u*

function mask_email( $email ) {
    
    $masked = '';

    $show_next = true;

    foreach ( str_split( $email ) as $chr ) {

      if ( $show_next ) {
        $masked .= $chr;
        $show_next = false;
      }
      else if ( in_array( $chr, array('.', '@', '+') ) ) {
        $masked .= $chr;
        $show_next = true;
      }
      else {
        $masked .= '*';
        $show_next = false;
      }

    }

    return $masked;
  }

Answer 17

非常简单的正则表达式方式：

$email = preg_replace('/\B[^@.]/', '*', $email)

结果：

john@smith.com：j***@s*****.c**

abcdef@example.org：a*****@e******.o**

abcdef：a*****

在PHP中部分隐藏电子邮件地址

17 个答案: