Question

我有两张桌子（比赛，球队）。在匹配表中我有id，team1，team2（其中team1和team2是团队的ID）。在团队表中我有id和名称..如何在php中打印匹配但显示团队名称而不是他们的ID？

我的代码（仅打印teamid vs teamid）：

<?php
    require_once 'conf/conf.php';
    require_once 'functions.php';
    $query = mysql_query("SELECT time1 as t1id, time2 as t2id
                        FROM matches
                        INNER JOIN teams
                        ON
                        teams.id = matches.time1
                        ");
    //echo mysql_num_rows($query);
    while ($row = mysql_fetch_assoc($query)) 
    {
        $t1 = $row["t1id"];
        $t2 = $row["t2id"];     
        echo ($t1 . " vs. " . $t2 . "<br>");
    }
?>

Answer 1

您可以执行以下操作（假设teams表格有name列）：

<?php
    require_once 'conf/conf.php';
    require_once 'functions.php';
    $query = mysql_query("SELECT time1 as t1id,
                                 time2 as t2id,
                                 t1.name AS t1name,
                                 t2.name AS t2name
                        FROM matches
                        INNER JOIN teams AS t1
                        ON t1.id = matches.time1
                        INNER JOIN teams AS t2
                        ON t2.id = matches.time2");
    //echo mysql_num_rows($query);
    while ($row = mysql_fetch_assoc($query)) 
    {
        $t1 = $row["t1name"];
        $t2 = $row["t2name"];     
        echo ($t1 . " vs. " . $t2 . "<br>");
    }
?>

Answer 2

试试这个

require_once 'conf/conf.php';
require_once 'functions.php';
$query = mysql_query("SELECT teams1.id as t1id,teams1.name as name1,  teams2.id as t2id,  teams2.name as name2
                    FROM matches
                    INNER JOIN teams as teams1 ON teams1.id = matches.time1
                    INNER JOIN teams as teams2 ON teams2.id = matches.time2
                    ");
//echo mysql_num_rows($query);
while ($row = mysql_fetch_assoc($query)) 
{
    $t1 = $row["name1"];
    $t2 = $row["name2"];     
    echo ($t1 . " vs. " . $t2 . "<br>");
}

Answer 3

正如我在对你的问题的评论中所说，加入桌子两次：</ p>

SELECT t1.name, t2.name
FROM matches.m
INNER JOIN teams AS t1 ON (t1.id = m.team1)
INNER JOIN teams AS t2 ON (t2.id = m.team2)

PHP上的内部联接

3 个答案: