根据列的总和计算加班

Question

我想计算每周超过40小时的工作时间。

table = shift_log_data
database = shift_logs

Field           Type            Null    Key     Default     Extra   
id              int(100)        NO      PRI     NULL    auto_increment
admin_hrs       decimal(20,2)   NO              0.00    
shop_hrs        decimal(20,2)   NO              0.00    
fab_hrs         decimal(20,2)   NO              0.00    
paint_hrs       decimal(20,2)   NO              0.00    
vacation_hrs    decimal(50,2)   NO              0.00    
control_hrs     decimal(20,2)   NO              0.00    
test_hrs        decimal(20,2)   NO              0.00    
engine_hrs      decimal(20,2)   NO              0.00    
hydraulic_hrs   decimal(20,2)   NO              0.00    
699_paint       varchar(100)    NO              0.00    
699_shop        varchar(100)    NO              0.00    
maint_hrs       varchar(100)    NO              0.00    
date            date            NO              NULL    
name            varchar(50)     NO              NULL    
job             varchar(50)     NO              NULL    

每周需要使用日期字段列admin_hrs到maint_hrs。{ 如果小时数超过每周40小时，请创建一个名为加班的别名，其余时间超过四十小时。

我试过了。

SELECT SUM(overtime)
  FROM
  (
    SELECT name,
           IF(SUM(test_hrs+fab_hrs+control_hrs+shop_hrs+paint_hrs+engine_hrs+hydraulic_hrs)>40,
             SUM(test_hrs+fab_hrs+control_hrs+shop_hrs+paint_hrs+engine_hrs+hydraulic_hrs))-40,
              0) AS overtime 
      FROM shift_log_data
     GROUP BY name
  ) TOTAL_OVERTIME

Answer 1

试试这个：

SELECT s.Name, YEAR(s.Date), WEEKOFYEAR(s.date),
      IF(SUM(test_hrs+fab_hrs+control_hrs+shop_hrs+paint_hrs+engine_hrs+hydraulic_hrs)>40,
          SUM(test_hrs+fab_hrs+control_hrs+shop_hrs+paint_hrs+engine_hrs+hydraulic_hrs))-40,
          0
         ) AS overtime 
FROM shift_log_data s
GROUP BY s.Name, YEAR(s.Date), WEEKOFYEAR(s.date);