我有一个在我的本地服务器上托管的html页面,apache2,我想将一些数据发送到python脚本并对其进行操作,我使用的是当我使用表单的 action 标记时,它不会导航到下一页,当我尝试Jquery时,脚本不会被执行。有帮助吗?提前谢谢。
HTML:
<body>
<div id="Header"></div>
<div id="wrapper">
<form name="login-form" class="login-form" action="/cgi-bin/test.py" method="post" onsubmit="validate();return false;">
<div class="header">
<h1>Enter Your Credentials</h1>
<span>URL,Admin,Tenant,Password</span>
</div>
<div class="content">
<input id="Uname" name="url" type="text" class="input username" placeholder="Keystone URL" />
<div class="user-icon"></div>
<input id="Pname"name="admin" type="password" class="input password" placeholder="Admin" />
<div class="pass-icon"></div>
<input id="oPass"name="password" type="password" class="input password" placeholder="Password" />
<div class="pass-icon"></div>
<input id="tenant"name="tenant" type="password" class="input password" placeholder="Tenant" />
<div class="pass-icon"></div>
</div>
<div class="footer">
<input type="submit" name="submit" value="Submit" class="button"/>
</div>
</form>
</div>
</body>
通过这种方式,脚本可以完美地执行,但不会导航到下一页。
Javascript功能:
function validate() {
var un = document.getElementById("Uname").value;
var valid = false;
var unArray = ["http://192.168.1.102:5000/v2.0"];
for (var i = 0; i < unArray.length; i++) {
if ((un == unArray[i])) {
valid = true;
break;
}
}
if (valid) {
alert("Login was successful");
location.href = 'HomePage.html';
document.login-form.action='/cgi-bin/test.py';
return false;
} else {
alert("Login was Unsuccessful");
return false;
}
}
这是我尝试的Ajax调用:
$.ajax({
type: "POST",
url: "/cgi-bin/test.py",
data: "stuff_for_python="+document.getElementById("Uname").value,
success: function(response) {
alert(response);
},
error: function(data) {
alert(data.responseText);
}
});
Python脚本:
#!/usr/bin/python
import cgi, cgitb
from StringIO import StringIO
import json
from io import BytesIO
import pycurl
cgitb.enable()
# Create instance of FieldStorage
form = cgi.FieldStorage()
# Get data from fields
url = form.getvalue('stuff_for_python')
print "Content-type: text/html\r\n\r\n\n"
print
print url
f = open('/home/stack/writing.txt','wb')
f.write(url)
f.close()
答案 0 :(得分:1)
问题在于邮寄的数据值 试试这个:
$.ajax(
{
type: "POST",
url: "/cgi-bin/test.py" ,
data: {stuff_for_python: document.getElementById("Uname").value},
success: function(response)
{
alert(response);
},
error: function(data)
{
alert(data.responseText);
},
});