Question

我想找到两个日期之间的区别。我试过这段代码，但它给了我错误的价值。我希望获得两个日期之间的总分钟数，因此我将小时数转换为分钟数并添加到分钟数。

var hourDiff = timeEnd - timeStart;
var diffHrs = Math.round((hourDiff % 86400000) / 3600000);
var diffMins = Math.round(((hourDiff % 86400000) % 3600000) / 60000);
diffMins = diffMins + (diffHrs * 60);

此处timeEnd为Mon Jan 01 2007 11:30:00 GMT+0530 (India Standard Time)，

且timeStart为Mon Jan 01 2007 11:00:00 GMT+0530 (India Standard Time)。

如果我得到1小时差异，那么它应该是0，而我得到的30分钟是正确的。但是时间应该是0。我在这里做错了吗？

Answer 1

尝试此代码（使用ms作为初始单位）

var timeStart = new Date("Mon Jan 01 2007 11:00:00 GMT+0530").getTime();
var timeEnd = new Date("Mon Jan 01 2007 11:30:00 GMT+0530").getTime();
var hourDiff = timeEnd - timeStart; //in ms
var secDiff = hourDiff / 1000; //in s
var minDiff = hourDiff / 60 / 1000; //in minutes
var hDiff = hourDiff / 3600 / 1000; //in hours
var humanReadable = {};
humanReadable.hours = Math.floor(hDiff);
humanReadable.minutes = minDiff - 60 * humanReadable.hours;
console.log(humanReadable); //{hours: 0, minutes: 30}

JSFiddle：http://jsfiddle.net/n2WgW/

Answer 2

试试这个：

var startDate = new Date('Jan 01 2007 11:00:00');
var endDate = new Date('Jan 01 2007 11:30:00');
var starthour = parseInt(startDate.getHours());
var endhour = parseInt(endDate.getHours());

if(starthour>endhour){
    alert('Hours diff:' + parseInt(starthour-endhour));
}
else{
    alert('Hours diff:' + parseInt(endhour-starthour));
}

这是工作fiddle。

Answer 3

尝试：

var diffHrs = Math.floor((hourDiff % 86400000) / 3600000);

Math.round将0.5小时差异调整为1。您只想获得小时变量中的“完整”小时数，是否使用Math.floor()

删除变量中的所有分钟数

Answer 4

您可以尝试以下操作：-

function diff_hours(dt2, dt1) 
 {

  var diff =(dt2.getTime() - dt1.getTime()) / 1000;
  diff /= (60 * 60);         // For Hours
  //diff /= (60);          For Minutes
  return Math.abs(Math.round(diff));

 }

dt1 = new Date(2014,10,2);
dt2 = new Date(2014,10,3);
console.log(diff_hours(dt1, dt2));            // you will get '24' hours


dt1 = new Date("October 13, 2014 08:11:00");
dt2 = new Date("October 13, 2014 11:13:00");
console.log(diff_hours(dt1, dt2));           // you will get '3' hours

Answer 5

如果您确信差异将小于24小时，则以下情况有效。

var timeStart= new Date('2015-01-01 03:45:45.890');
var timeEnd = new Date('2015-01-01 05:12:34.567');
var timeDiff = new Date(timeEnd.getTime() - timeStart.getTime());
var humanTime = timeDiff.toISOString().substring(11, 23);
var diffHours = timeDiff.toISOString().substring(11, 12);

humanTime是01：26：48.677，diffHours是01

Answer 6

var timeDiff = function (date1, date2) {
        var a = new Date(date1).getTime(),
            b = new Date(date2).getTime(),
            diff = {};

        diff.milliseconds = a > b ? a % b : b % a;
        diff.seconds = diff.milliseconds / 1000;
        diff.minutes = diff.seconds / 60;
        diff.hours = diff.minutes / 60;
        diff.days = diff.hours / 24;
        diff.weeks = diff.days / 7;

        return diff;
    }

Answer 7

您可以通过使用以下内容获得小时分钟和倒计时之间的时差：

var diff = EndedTime - StartedTime;
var hours   = Math.floor(diff / 3.6e6);
var minutes = Math.floor((diff % 3.6e6) / 6e4);
var seconds = Math.floor((diff % 6e4) / 1000);
var duration = hours+":"+minutes+":"+seconds;

希望这个帮助。感谢

Answer 8

您可以按照以下小时和分钟格式获取时差

const startTime = new Date(event.startTime);
const endTime = new Date(event.endTime);
const diff = endTime.getTime() - startTime.getTime();
const hrDiff = diff / 3600 / 1000; // 1.555555
const totalHours = parseFloat((hrDiff).toFixed(2)); // 1.5

两分钟之间的差异，分钟，小时javascript

8 个答案: