Question

我有以下查询：\

SELECT *

FROM   (SELECT 1 CntCol, CONVERT(CHAR(3), [data out (no val#vuoto)], 0) month, 
               ( [gruppi min (gg flusso/decorrenza-->out)] ) 
        FROM   dbpratiche 
        WHERE  compagnia = 'GENERALI INA ASSITALIA' 
               AND stato = 'OUT ATTIVATA' 
               AND [data out (no val#vuoto)] > '01-01-2012') TLB 
       PIVOT ( Count(CntCol) 
             FOR tlb.month IN([nov], 
                              [dec], 
                              [jan], 
                              [feb], 
                              [mar], 
                              [apr],
                              [May],
                              [jun],
                              [jul],
                              [aug],
                              [sep],
                              [oct] ) )PVT

此pivotote查询产生以下结果：

enter image description here

我想再次调整此表格以获得结果：

Months  <=06   <=8  <=10   >10

Jan     0       1    1      6

Feb     8       5    4      2

Mar     9       7    6      2

请帮忙。

Answer 1

试试这段代码：

  SELECT *
  FROM   (SELECT 1 CntCol, CONVERT(CHAR(3), [data out (no val#vuoto)], 0) month, 
           ( [gruppi min (gg flusso/decorrenza-->out)] ) 
       FROM   dbpratiche 
       WHERE  compagnia = 'GENERALI INA ASSITALIA' 
           AND stato = 'OUT ATTIVATA' 
           AND [data out (no val#vuoto)] > '01-01-2012') TLB 
   PIVOT ( Count(CntCol) 
         FOR tlb.[gruppi min (gg flusso/decorrenza-->out)] IN
                         ([<=06], 
                          [<=08], 
                          [<=10], 
                          [>10] ) )PVT

Answer 2

我自己解决了这个问题：

select * from
(
  SELECT 1 CntCol, CONVERT(CHAR(3), [data out (no val#vuoto)], 0) month, 
               ( [gruppi min (gg flusso/decorrenza-->out)] ) 
        FROM   dbpratiche 
        WHERE  compagnia = 'GENERALI INA ASSITALIA' 
               AND stato = 'OUT ATTIVATA' 
               AND [data out (no val#vuoto)] > '01-01-2012'
) T
pivot
(
  count(cntcol)
  for [gruppi min (gg flusso/decorrenza-->out)]
  in([>10],[<=10],[<=06],[<=08])

)P

Answer 3

你似乎想要的是让枢轴反过来。我建议你试试这个：

SELECT *
FROM   (SELECT 1 CntCol, CONVERT(CHAR(3), [data out (no val#vuoto)], 0) month, 
               ( [gruppi min (gg flusso/decorrenza-->out)] as gg) 
        FROM   dbpratiche 
        WHERE  compagnia = 'GENERALI INA ASSITALIA' 
               AND stato = 'OUT ATTIVATA' 
               AND [data out (no val#vuoto)] > '01-01-2012') TLB 
       PIVOT ( Count(CntCol) 
             FOR tlb.gg IN([<=06], 
                              [<=08], 
                              [<=10], 
                              [>10]
                              ) )PVT

如果您的列中包含的值超过了上述值，请查看动态sql，如here

旋转枢轴表

3 个答案: