Question

我正在使用SQL Server 2008.我有两个表Shift和Break以及以下数据：班次将是每周7天。

SHIFT TABLE中的数据

ID  Desc Start_Time End_Time
1   1st 07:20:00    15:20:00
2   2nd 15:20:00    23:20:00
3   3rd 23:20:00    07:20:00

BREAK TABLE中的数据

ID  Desc                    Start_Time  End_Time
1   1st Shift - 1st break   09:10:00    09:25:00
2   1st Shift - Lunch       11:30:00    12:05:00
3   1st Shift - 2nd break   13:30:00    13:45:00
4   2nd Shift - 1st break   17:10:00    17:25:00
5   2nd Shift - Lunch       19:30:00    20:05:00
6   2nd Shift - 2nd break   21:30:00    21:45:00
7   3rd Shift - 1st break   01:10:00    01:25:00
8   3rd Shift - Lunch       03:30:00    04:05:00
9   3rd Shift - 2nd break   05:30:00    05:45:00

输出必须是：

Start_Time   End Time
07:20:00     09:10:00
09:25:00     11:30:00
12:05:00     13:30:00
13:30:00     15:20:00
....

我是新人加入，任何人都可以帮助我加入。此外，如果您认为表格结构的任何变化都会有所帮助，请提出建议。

Answer 1

正如其他人所说，如果不做一些事情，这有点模糊。有更快，更简单的方法来处理这个问题，但我尽量使我的解决方案尽可能动态，以适应模糊的定义。以下是我的假设：

这是SQL小提琴：SQL Fiddle Demo

<强>假设

假设SQL Server 2005 +
假设班次表日期部分为1900-01-01
假设Break表具有StartTime / EndTime的正确日期
假设数据库中只有1个人进出时间（No EmployeeID包含在@BREAK表中）
假设他们全班工作。正好在班次时钟在班次开始和结束。

<强>表格

DECLARE @SHIFT Table (ID INT IDENTITY(1,1) PRIMARY KEY, StartTime DATETIME, EndTime DATETIME)
INSERT INTO @SHIFT (StartTime, EndTime) VALUES 
('07:20:00','15:20:00'),
('15:20:00','23:20:00'),
('23:20:00','07:20:00')

DECLARE @BREAK Table (ID INT IDENTITY(1,1) PRIMARY KEY, StartTime DATETIME, EndTime DATETIME)
INSERT INTO @BREAK (StartTime, EndTime) VALUES
('1/1/2013 09:10:00','1/1/2013 09:25:00'),
('1/1/2013 11:30:00','1/1/2013 12:05:00'),
('1/1/2013 13:30:00','1/1/2013 13:45:00'),
('1/1/2013 17:10:00','1/1/2013 17:25:00'),
('1/1/2013 19:30:00','1/1/2013 20:05:00'),
('1/1/2013 21:30:00','1/1/2013 21:45:00'),
('1/2/2013 01:10:00','1/2/2013 01:25:00'),
('1/2/2013 03:30:00','1/2/2013 04:05:00'),
('1/2/2013 05:30:00','1/2/2013 05:45:00'),

('1/2/2013 09:10:00','1/2/2013 09:25:00'),
('1/2/2013 11:30:00','1/2/2013 12:05:00'),
('1/2/2013 13:30:00','1/2/2013 13:45:00'),
('1/2/2013 17:10:00','1/2/2013 17:25:00'),
('1/2/2013 19:30:00','1/2/2013 20:05:00'),
('1/2/2013 21:30:00','1/2/2013 21:45:00'),
('1/2/2013 01:10:00','1/2/2013 01:25:00'),
('1/2/2013 03:30:00','1/2/2013 04:05:00'),
('1/2/2013 05:30:00','1/2/2013 05:45:00')

<强>解决方案

;WITH
MinMaxDates AS --FINDS THE MINIMUM AND MAXIMUM DATE RANGES NEEDING SHIFTS ASSOCIATED.
(
    SELECT 
        CAST(MIN(B.StartTime) AS DATE) AS MinDate, 
        CAST(MAX(B.EndTime) AS DATE) AS MaxDate 
    FROM @BREAK AS B
),
RecursiveDateBuilder AS --RECURSIVELY BUILDS A LIST OF DATES BETWEEN THE MINIMUM AND MAXIMUM RANGES IN BREAKS
(
    SELECT MinDate AS ShiftStartDate FROM MinMaxDates
    UNION ALL
    SELECT DATEADD(dd,1,ShiftStartDate) FROM RecursiveDateBuilder WHERE DATEADD(dd,1,ShiftStartDate) <= (SELECT MaxDate FROM MinMaxDates)
),
ShiftSets AS --CREATE A SHIFT SET FOR EVERY DATE
(
    SELECT 
        ROW_NUMBER() OVER (ORDER BY R.ShiftStartDate ASC, S.ID ASC) AS NewShiftID,
        S.ID AS OldShiftID, 
        DATEADD(dd,DATEDIFF(dd,S.StartTime, R.ShiftStartDate),S.StartTime) AS StartDate,
        DATEADD(dd,DATEDIFF(dd,S.EndTime, R.ShiftStartDate),S.EndTime) AS EndDate,
        R.ShiftStartDate AS ShiftGroup
    FROM
        @SHIFT AS S
        CROSS JOIN RecursiveDateBuilder AS R
),
Shifts AS  --FIXES ANY SHIFTS THAT CROSS MIDNIGHT SETTING THEM TO THE NEXT DAY
(
SELECT
    S.NewShiftID AS ShiftID,
    S.StartDate,
    CASE 
        WHEN S.EndDate <= Min2.MinStartDate THEN DATEADD(DAY,1,S.EndDate) 
        ELSE S.EndDate 
    END AS EndDate
FROM
    ShiftSets AS S
    CROSS APPLY (SELECT MIN(Mins.StartDate) AS MinStartDate FROM ShiftSets AS Mins WHERE Mins.ShiftGroup = S.ShiftGroup) AS Min2 
),
BreaksToShifts AS  --ASSOCIATES THE PUNCHES TO THE SHIFTS
(
    SELECT
        B.StartTime AS ClockIn,
        B.EndTime AS ClockOut,
        S.ShiftID,
        S.StartDate,
        S.EndDate
    FROM
        @BREAK AS B
        INNER JOIN Shifts AS S ON (B.StartTime BETWEEN S.StartDate AND S.EndDate AND B.EndTime BETWEEN S.StartDate AND S.EndDate)
),
Punches AS
(
    SELECT ROW_NUMBER() OVER (ORDER BY S.TheTime ASC) AS ID, S.TheTime FROM 
    (
        SELECT BS.ShiftID, BS.ClockIn AS TheTime FROM BreaksToShifts AS BS
        UNION ALL
        SELECT BS.ShiftID, MIN(BS.StartDate) AS TheTime FROM BreaksToShifts AS BS GROUP BY BS.ShiftID
        UNION ALL
        SELECT BS.ShiftID, BS.ClockOut AS TheTime FROM BreaksToShifts AS BS
        UNION ALL
        SELECT BS.ShiftID, MAX(BS.EndDate) AS TheTime FROM BreaksToShifts AS BS GROUP BY BS.ShiftID
    ) AS S
)
SELECT
    *
FROM
    Punches AS P1
    INNER JOIN Punches AS P2 ON (P2.ID = P1.ID + 1)
WHERE
    P1.ID % 2 > 0

从Shift和Break Table计算工作时间

1 个答案: