我是CI新手,我在以下代码中遇到问题:我的控制器动态显示来自数据库的国家/地区的所有值,我需要将特定chechbox的值传递给我的控制器
我的观点代码是:
<?php foreach ( $countryDetails as $row ) {
echo '<input id="country" type="checkbox" name="country" class="unique" value="'.$row->country_id.'">'.$row->country_name.'<br/>';
}?>
<script>
$('input.unique').click(function() {
$('input.unique:checked').not(this).removeAttr('checked');
});
$(document).ready(function(){
$(document).on('click','.unique',function(){
var id=this.value;
$.ajax({
type: "POST",
context: "application/json",
data: {id:id},
url: "http://localhost/index.php/fetch_country/index",
success: function(msg){
alert('$id ');
}
});
});
});
</script>
控制器:
public function index() {
$this->view_data['countryDetails'] = $this->get_county_model->getCountryDetails();
$this->load->view('get_country' , $this->view_data );
}
public function fetch() {
$id=$this->input->post('id');
echo ('$id');
}
答案 0 :(得分:0)
$(document).on('click','.unique',function(){
var id=$(this).val();
$.ajax({
type: "POST",
context: "application/json",
data: {id:id},
url: "http://localhost/index.php/fetch_country/index",
success: function(msg){
alert(msg);
}
});
});
public function fetch() {
$id=$this->input->post('id');
echo $id;
}