我有一张这样的桌子。
+----+-------+---------+----------+---------+----------+---------+----------+ | id | Month | Debit_A | Credit_A | Debit_B | Credit_B | Debit_C | Credit_C | +----+-------+---------+----------+---------+----------+---------+----------+ | 1 | Jan | 100.50 | | | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 2 | Jan | | 100.50 | | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 3 | Jan | 150.25 | | | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 4 | Jan | | | | | 300.00 | | +----+-------+---------+----------+---------+----------+---------+----------+ | 5 | Jan | | | | | | 300.00 | +----+-------+---------+----------+---------+----------+---------+----------+ | 6 | Feb | | | 79.80 | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 7 | Feb | | | | 79.80 | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 8 | Feb | | | 200.00 | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 9 | Feb | | | | 200.00 | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 10 | Mar | | | | | 1500.00 | | +----+-------+---------+----------+---------+----------+---------+----------+ | 11 | Mar | | | | | | 1500.00 | +----+-------+---------+----------+---------+----------+---------+----------+ | 12 | Apr | 100.00 | | | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 13 | Apr | | 50.00 | | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 14 | May | | | 50.75 | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 15 | May | | | | 50.70 | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 16 | Jun | | | | | 75.50 | | +----+-------+---------+----------+---------+----------+---------+----------+ | 17 | Jun | | | | | | 75.50 | +----+-------+---------+----------+---------+----------+---------+----------+ | 18 | Jun | | | | | 75.50 | | +----+-------+---------+----------+---------+----------+---------+----------+ | 19 | Jun | | | | | | 75.50 | +----+-------+---------+----------+---------+----------+---------+----------+ | 20 | Jul | 89.50 | | | | | | +----+-------+---------+----------+---------+----------+---------+----------+
我想要的是将具有相同Month值和相同Debit / Credit值的行组合到新表中。这会将借记和贷记行合并为一行。 例如：
+----+-------+---------+----------+---------+----------+---------+----------+ | id | Month | Debit_A | Credit_A | Debit_B | Credit_B | Debit_C | Credit_C | +----+-------+---------+----------+---------+----------+---------+----------+ | 1 | Jan | 100.50 | 100.50 | | | 300.00 | 300.00 | +----+-------+---------+----------+---------+----------+---------+----------+ | 2 | Jan | 150.25 | | | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 3 | Feb | | | 79.80 | 79.80 | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 4 | Feb | | | 200.00 | 200.00 | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 5 | Mar | | | | | 1500.00 | 1500.00 | +----+-------+---------+----------+---------+----------+---------+----------+ | 6 | Apr | 100.00 | | | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 7 | Apr | | 50.00 | | | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 8 | May | | | 50.75 | 50.70 | | | +----+-------+---------+----------+---------+----------+---------+----------+ | 9 | Jun | | | | | 75.50 | 75.50 | +----+-------+---------+----------+---------+----------+---------+----------+ | 10 | Jun | | | | | 75.50 | 75.50 | +----+-------+---------+----------+---------+----------+---------+----------+ | 11 | Jul | 89.50 | | | | | | +----+-------+---------+----------+---------+----------+---------+----------+
如何在SQL Server 2008或SQL Server 2012中执行此操作？
答案 0 :(得分：0)
如果我是你，我有两个解决方案可以实现这一目标：
对于临时表
<强>更新
SELECT id, Month, 0 AS Debit_A, 0 AS Credit_A, 0 AS Debit_B, 0 AS Credit_B, 0 AS Debit_C, 0 AS Credit_C
INTO #TempTable
FROM YourTable
GROUP BY Month
UPDATE T
SET Debit_A = Value
FROM #TempTable T
INNER JOIN DebitATable D
ON T.Month = D.Month
我会使用类似的东西（抱歉，因为它不太通用，因为我不知道数据库的结构）
您可以使用GROUP或SUM获取您在借记卡或信用卡值中获得的值
答案 1 :(得分：0)
-- 1st we import the raw account activity data
IF OBJECT_ID('dbo.RawActivity','U') IS NOT NULL
DROP TABLE dbo.RawActivity;
GO
-- for the sake of mnemonics--and precedence when ordering--transactions
-- for account A, B, C and so on are defined as 0 for debits and 1 for
-- credits, and month short names are replaced with their number
CREATE TABLE dbo.RawActivity(id int,
M int,
A0 money,
A1 money,
B0 money,
B1 money,
C0 money,
C1 money);
GO
INSERT dbo.RawActivity
VALUES
(1, 1, 100.50, NULL, NULL, NULL, NULL, NULL),
(2, 1, NULL, 100.50, NULL, NULL, NULL, NULL),
(3, 1, 150.25, NULL, NULL, NULL, NULL, NULL),
(4, 1, NULL, NULL, NULL, NULL, 300.00, NULL),
(5, 1, NULL, NULL, NULL, NULL, NULL, 300.00),
(6, 2, NULL, NULL, 79.80, NULL, NULL, NULL),
(7, 2, NULL, NULL, NULL, 79.80, NULL, NULL),
(8, 2, NULL, NULL, 200.00, NULL, NULL, NULL),
(9, 2, NULL, NULL, NULL, 200.00, NULL, NULL),
(10 ,3, NULL, NULL, NULL, NULL, 1500.00, NULL),
(11, 3, NULL, NULL, NULL, NULL, NULL, 1500.00),
(12, 4, 100.00, NULL, NULL, NULL, NULL, NULL),
(13, 4, NULL, 50.00, NULL, NULL, NULL, NULL),
(14, 5, NULL, NULL, 50.75, NULL, NULL, NULL),
(15, 5, NULL, NULL, NULL, 50.70, NULL, NULL),
(16, 6, NULL, NULL, NULL, NULL, 75.50, NULL),
(17, 6, NULL, NULL, NULL, NULL, NULL, 75.50),
(18, 6, NULL, NULL, NULL, NULL, 75.50, NULL),
(19, 6, NULL, NULL, NULL, NULL, NULL, 75.50),
(20, 7, 89.50, NULL, NULL, NULL, NULL, NULL);
GO
-- 2nd we are going to flatten the raw data into a spagetti of transactions
-- with type T and parent transaction
IF OBJECT_ID('dbo.Activity','U') IS NOT NULL
DROP TABLE dbo.Activity;
GO
CREATE TABLE dbo.Activity(id int, M int, amount money, T char(2), pid int);
GO
INSERT INTO dbo.Activity
SELECT id,
M,
-- amount: the 1st non null
ISNULL(A0, ISNULL(A1, ISNULL(B0, ISNULL(B1, ISNULL(C0, C1))))),
-- type
CASE
WHEN A0 IS NOT NULL THEN 'A0'
WHEN A1 IS NOT NULL THEN 'A1'
WHEN B0 IS NOT NULL THEN 'B0'
WHEN B1 IS NOT NULL THEN 'B1'
WHEN C0 IS NOT NULL THEN 'C0'
WHEN C1 IS NOT NULL THEN 'C1'
END,
-- parent id
NULL
FROM dbo.RawActivity;
-- 3rd it gets interesting; we update the parent id with the 1st transaction
-- of each month, with help from FIRST_VALUE...
UPDATE dbo.Activity SET pid = P.pid
FROM
(
SELECT P.id,
FIRST_VALUE(A.id) OVER(PARTITION BY A.M ORDER BY A.M, A.id) AS pid
FROM dbo.Activity AS P INNER JOIN
dbo.Activity AS A ON P.id = A.id
) AS P
WHERE dbo.Activity.id = P.id;
-- we update same month and type transactions parent so that they are not
-- added together...
UPDATE A
SET A.pid = A.id
FROM dbo.Activity AS A JOIN
dbo.Activity AS B ON A.pid = B.id AND A.T = B.T AND A.M = B.M;
-- and we look for (type, parent) duplicates to update the parent; this
-- catches subsequent transactions of the same type. The naming of
-- transaction types pays off here because of the partitioning, and
-- the new parent will be the transaction right above the duplicate
-- TODO: test with more than two consecutive transactions of the same
-- type (there is none in your data)
WITH Duplicates AS
(
SELECT *, ROW_NUMBER() OVER(PARTITION BY T, pid ORDER BY id) AS r FROM dbo.Activity
)
UPDATE Duplicates SET pid = id - 1 WHERE r > 1;
-- finally, we can pivot the whole thing to get back to the desired output;
-- the outer SELECT statement is just for beautification.
SELECT ROW_NUMBER() OVER(ORDER BY M) AS id,
FORMAT(DATEFROMPARTS(YEAR(GETDATE()), M, 1), 'MMM') AS [Month],
A0 AS Debit_A,
A1 AS Credit_A,
B0 AS Debit_B,
B1 AS Credit_B,
C0 AS Debit_C,
C1 AS Credit_C
FROM
(
SELECT M,
SUM([A0]) AS A0,
SUM([A1]) AS A1,
SUM([B0]) AS B0,
SUM([B1]) AS B1,
SUM([C0]) AS C0,
SUM([C1]) AS C1
FROM
(
SELECT id, M, amount, T, pid FROM dbo.Activity
) AS A
PIVOT
(
SUM(amount)
FOR T IN ([A0], [A1], [B0], [B1], [C0], [C1])
) AS PVT
GROUP BY M, pid
) AS Result;
答案 2 :(得分：-1)
Jan应该只有一行，而Debit_A = 250.75？ 在标准SQL中，我猜你可以使用它，不确定它是否适合sql-server：
select sum(debit_a), sum(debit_b), .. from table name group by month;