Question

我目前正在使用Java编写程序。这是一个卡片游戏，您必须猜测三张牌（4,5或6）随机生成的数字。如果你猜对了正确的数字，你就赢了。如果您第一次没有按照正确的顺序猜测这些数字，您可以只重试一张卡。到目前为止，所有这些我都开始工作，但是当我想要改变我的第二个或第三个答案时，我必须两次输入'2'或三次输入'3'来更换这些卡。这是我的代码：

package cardgame;

import java.util.Scanner;

public class CardGame {

public static void main(String[] args){

    Scanner scan = new Scanner(System.in);
    int[] guess = new int[3];
    int[] card = new int[3];

    System.out.println("Pick three cards with numbers ranging from 4 to 6!\n");

    for (int i=0; i<3; i++){
       System.out.print("Card number " + (i+1) + " (4, 5 or 6): ");
       guess[i] = scan.nextInt();
       }
       System.out.println(" ");
       System.out.println("Your hand of cards: " + "[" + guess[0] + "]" + "[" + guess[1] + "]" + "[" + guess[2] + "]");

    for (int i=0; i<3; i++){
       card[i] = (int) (Math.random() * 3 + 2 +2);
       }

       int count = 0;
       for (int i=0; i<3; i++){
    if (card[i] == guess[i])
       count++;
          }

    if (count == 3){
       System.out.println("My hand of cards: " + "[" + card[0] + "]" + "[" + card[1] + "]" + "[" + card[2] + "]\n");
       System.out.println("Congratulations, you have won!\nType 'end' to end the game and I will show you my hand of cards.");
       } else{
       System.out.println("Not quite yet there!\n");
       }

    if (count !=3){
       System.out.println("Would you like to change one of your guesses? yes/no");
       }

    if("yes".equals(scan.next())){
       System.out.println("\nWhat card would you like to change? 1/2/3");
       {

    if(scan.nextInt() == 1 || scan.nextInt() == 2 || scan.nextInt() == 3){
       System.out.println("\nWhat is your new guess?");
       int secondGuess = scan.nextInt();

    if (secondGuess == card[0] || secondGuess == card[1] || secondGuess == card[2]){
        count++;  
       }

    if (count == 3){
       System.out.println("\nCongratulations, you have won!");
       } else{
       System.out.println("\nI'm sorry, you lost!");
       }
     }
   }      
 }
       // Print the 3 random numbers card[0], card[1] and card[2]
       System.out.println("My hand of cards: " + "[" + card[0] + "]" + "[" + card[1] + "]" + "[" + card[2] + "]\n");
    }
  }

到目前为止的输出：

Pick three cards with numbers ranging from 4 to 6!

Card number 1 (4, 5 or 6): 4

Card number 2 (4, 5 or 6): 5

Card number 3 (4, 5 or 6): 6

Your hand of cards: [4][5][6]

Not quite yet there!

Would you like to change one of your guesses? yes/no

yes

What card would you like to change? 1/2/3

2

2

What is your new guess?

6

Congratulations, you have won!

My hand of cards: [4][4][6]

如您所见，我必须插入两次。另外我在第二个位置的新猜测是6，并且在第二个位置应该是4。我哪里出错了？我似乎无法解决它。

Answer 1

您在此行中最多调用scan.nextInt次

if(scan.nextInt() == 1 || scan.nextInt() == 2 || scan.nextInt() == 3){

根据您键入的数字，最多可读取三个数字。

第一个数字是1：只读取一个数字。
第一个数字不是1，第二个数字是2：读取两个数字。
否则，读取3个数字。

抓住一次，然后比较一下：

int someNumber = scan.nextInt();
if(someNumber  == 1 || someNumber  == 2 || someNumber  == 3){

用Java改变你自己的答案

1 个答案: