Question

import requests
import json

# initial message
message = "if i can\'t let it go out of my mind"

# split into list
split_message = message.split()

def decrementList(words):
    for w in [words] + [words[:-x] for x in range(1,len(words))]:
        url = 'http://ws.spotify.com/search/1/track.json?q='
        request = requests.get(url + "%20".join(w))

        json_dict = json.loads(request.content)
        num_results = json_dict['info']['num_results']
        if num_results > 0:
            num_removed = len(words) - len(w)

            #track_title = ' '.join(words)

            track_title = "If I Can't Take It with Me"

            for value in json_dict.items():
                if value == track_title:
                    print "match found"

            return num_removed, json_dict


num_words_removed, json_dict = decrementList(split_message)

在下面的代码中，我尝试将歌曲的名称与我的搜索查询相匹配。在此特定查询中，歌曲将不匹配，但我添加了一个与返回查询的歌曲匹配的变量。函数末尾的for循环应该与track标题变量匹配，但我无法弄清楚它为什么不起作用。有没有一种简单的方法来查找已知密钥的所有值？在这种情况下，键是“名称”

Answer 1

您必须在tracks词典中搜索曲目标题。所以，只需像这样更改你的代码

for value in json_dict["tracks"]:
    if value["name"] == track_title:

它会打印

match found

如何在python中查找特定键的值

1 个答案: