Question

我遇到了观看 Swig.js html模板并在每次更改时编译它们的问题，为此，我使用 Gulp.js 任务运行器。这是我的 gulpfile.js ：

var gulp = require('gulp');
var myth = require('gulp-myth');
var swig = require('gulp-swig');
var nodemon = require('gulp-nodemon');

gulp.task('styles', function () {
  gulp.src('./myth/*.css')
    .pipe(myth())
    .pipe(gulp.dest('./client/css'));
});

gulp.task('templates', function () {
  gulp.src('./views/*.html')
    .pipe(swig({ load_json: true }))
    .pipe(gulp.dest('./client'));
});

gulp.task('server', function () {
  gulp.run('styles');
  gulp.run('templates');

  gulp.src('./server.js').pipe(nodemon());

  gulp.watch('./myth/*.css', function () {
     gulp.run('styles');
  });

  gulp.watch('./views/*.html', function () {
     gulp.run('templates');
  }); 
});

神话任务样式运行良好 - myth/*.css的每次更改都在client/css/中获得了更新文件。

但是名为 templates 的任务只给出了一次结果..当我在views/index.html中更改client/index.html文件时保持不变。在我的控制台中，我看到 templates 任务已运行，但结果仍然相同..

MacBook-Pro-Dmitri:slick-grid dmitri$ gulp server
[gulp] Using file /Users/dmitri/github/slick-grid/gulpfile.js
[gulp] Working directory changed to /Users/dmitri/github/slick-grid
[gulp] Running 'server'...
[gulp] Running 'styles'...
[gulp] Finished 'styles' in 4.02 ms
[gulp] Running 'templates'...
[gulp] Finished 'templates' in 1.29 ms
[gulp] Running 'watch'...
[gulp] Finished 'watch' in 7.23 ms
[gulp] Finished 'server' in 16 ms
>> Strata web server version 0.20.1 running on node 0.10.21
>> Listening on 0.0.0.0:9000, CTRL+C to stop

// Here I changed my views/index.html, task is ran as you see (but dest file won't be updated):

[gulp] Running 'templates'...
[gulp] Finished 'templates' in 668 μs 
127.0.0.1 - - [11/Jan/2014:15:43:20 +-200] "GET / HTTP/1.1" 200 511
127.0.0.1 - - [11/Jan/2014:15:43:20 +-200] "GET /css/reset.css HTTP/1.1" 200 1419
127.0.0.1 - - [11/Jan/2014:15:43:20 +-200] "GET /css/app.css HTTP/1.1" 200 865
127.0.0.1 - - [11/Jan/2014:15:43:20 +-200] "GET /fonts/likeastore-icon-font.ttf HTTP/1.1" 200 15052

也许我错过了一些缓存选项或类似的东西？！

Answer 1

Gulp-Swig已更新为允许禁用缓存选项 - 以及设置其他swig默认值，如下所示。

gulp.task('templates', function() {
  gulp.src('./views/*.html')
    .pipe(swig({
      load_json: true,
      defaults: {
        cache: false,
        locals: {
          site_name: "My Blog"
        }
      }
    }))
    .pipe(gulp.dest('./client'));
});

Answer 2

编辑：配置可能不再有效，根据Mike Aski的评论

我遇到了类似的问题，gulp-livereload和tiny-lr正在刷新页面，但没有显示更新的模板。我没有使用gulp-swig（虽然这看起来很不错），所以我刚刚更改了 app.js ：

swig = require("swig");

swig.setDefaults({
  cache: false
});

app = express();

app.set('view cache', false);

Gulp.js - 在更改时观察并编译swig.js模板文件

2 个答案: