Question

我已经查看了stackoverflow上的多个示例，但无法使其工作。

这是我需要以编程方式登录的网址：http://powerschool.fortschools.org/public/

我尝试了很多不同的方法，但都没有成功。这是我目前所拥有的：

登录前的

原始网址：http://powerschool.fortschools.org/public/

登录后的网址：http://powerschool.fortschools.org/guardian/home.html

表格我认为是在登录前提交的：

<form action="/guardian/home.html" method="post" name="LoginForm" target="_top" id="LoginForm" onsubmit="doPCASLogin(this);">
<input type="hidden" name="pstoken" value="308732667SkW2oaVnhxqIqM5PzqdGWrXW4jdQoB8W">
<input type="hidden" name="contextData" value="2AA011214C3F506D76216C5B459574636E2269F51AC438EB11081A7C735345A8">
<input type="hidden" name="dbpw" value="">
<input type="hidden" name="translator_username" value="">
<input type="hidden" name="translator_password" value="">
<input type="hidden" name="translator_ldappassword" value="">

<input type="hidden" name="returnUrl" value="">
<input type="hidden" name="serviceName" value="PS Parent Portal">
<input type="hidden" name="serviceTicket" value="">
<input type="hidden" name="pcasServerUrl" value="/">
<input type="hidden" name="credentialType" value="User Id and Password Credential">

<h2>Parent Sign In</h2>
<!--box content-->
<div id="noscript" class="feedback-alert" style="display: none;"> To sign in to PowerSchool, you must use a browser that supports and has JavaScript enabled. </div>
<fieldset id="login-inputs" class="group">
<div>
  <label>Username</label>
  <input type="text" id="fieldAccount" name="account" value="" size="39">
</div>
<div>
  <label>Password</label>
  <input type="password" name="pw" value="" size="39"><div id="login-help"><a href="/public/account_recovery_begin.html">Having trouble signing in?</a></div>
</div>
<div id="translatorInput" style="display: none;">
  <label>Translator Sign In</label>
  <input type="password" name="translatorpw" value="" size="39">
</div>
<div class="button-row">
  <button type="submit" id="btn-enter" title="Sign In To PowerSchool Parent Access" value="Enter" border="0">Sign In</button>
</div>
</fieldset>       
<!-- box content-->
</form>

按下提交按钮后，表单将更改为此（仅dbpw更改，（这是两个单独的示例，因此pstoken和contextData确实发生了更改））： Notice how the only thing that changes is the dbpw field

这是在你“完全登录”之后 Data respone headers cookies

这是我的代码（不工作）：

public static final String POWERSCHOOLLOGINURL = "http://powerschool.fortschools.org/public/";
    public static final String POWERSCHOOLLOGIN = "http://powerschool.fortschools.org/guardian/home.html";

    public static void main(String[] args) throws IOException {
        Map<String, String> nameToVal = new HashMap<String, String>();
        nameToVal.put("pstoken", "308732667b2uBDHKHeNJc1XTXdgDSVwxzHfzldM9M");
        nameToVal.put("contextData", "e1c94866f2ed77f3ae37bc1a2a477631");
        nameToVal.put("dbpw", "29e3fdf45f7959a5e0c894ad01b34941");
        nameToVal.put("translator_username", "");
        nameToVal.put("translator_password", "");
        nameToVal.put("translator_ldappassword", "");
        nameToVal.put("returnUrl", "");
        nameToVal.put("serviceName", "PS Parent Portal");
        nameToVal.put("serviceTicket", "");
        nameToVal.put("pcasServerUrl", "/");
        nameToVal.put("credentialType", "User Id and Password Credential");
        nameToVal.put("account", "horvste");
        nameToVal.put("translatorpw", "");
        nameToVal.put("returnUrl", "");
        nameToVal.put("pcasServerUrl", "/");
        nameToVal.put("credentialType", "User Id and Password Credential");
        Map<String, String> cookies = new HashMap<String, String>();
        cookies.put("JSESSIONID", "2C108FB2394FFE097E366BC3C34827B8");
        cookies.put("lastHref",
                "http%3A%2F%2Fpowerschool.fortschools.org%2Fguardian%2Fhome.html");
        cookies.put("uiStateCont", "null");
        cookies.put("uiStateNav", "null");

        Document doc = Jsoup.connect(POWERSCHOOLLOGIN).cookies(cookies)
                .data(nameToVal).method(Method.POST).post();
        System.out.println(doc.toString());

    }

注意：HtmlUnit不是一个可接受的答案（它会减慢并且不适用于android）。

Answer 1

您必须模拟md5.js（可以在dev工具的资源选项卡中找到）与提交表单一起使用：

    function doPCASLogin(form) {
   var originalpw = form.pw.value;
   var b64pw = b64_md5(originalpw);
   var hmac_md5pw = hex_hmac_md5(pskey, b64pw)
   form.pw.value = hmac_md5pw;
   form.dbpw.value = hex_hmac_md5(pskey, originalpw.toLowerCase())
   if (form.ldappassword!=null) {
     // LDAP is enabled, so send the clear-text password
     // Customers should have SSL enabled if they are using LDAP
     form.ldappassword.value = originalpw; // Send the unmangled password
   }

   // Translator Login
   var translatorpw = form.translatorpw.value;
   var i = translatorpw.indexOf(";");
    if (i < 0) {
        form.translator_username.value = translatorpw;
        form.translator_password.value = "";
    }
    else {
        form.translator_username.value = translatorpw.substring(0,i);
        translatorpw = translatorpw.substring(i+1); // Get the password
        translatorpw2 = translatorpw;
        translatorpw = b64_md5(translatorpw);                   // Added in move to pcas
        form.translator_password.value = hex_hmac_md5(pskey, translatorpw);
        if (form.translator_ldappassword!=null) {
            // LDAP is enabled, so send the clear-text password
            // Customers should have SSL enabled if they are using LDAP
            form.translator_ldappassword.value = translatorpw2; // Send the pw for LDAP
        }
    }

    return true;
}

Answer 2

我有不同的方法。我知道我的代码是 PHP，而不是 Java，但它仍然可能激发人们将其改编成另一种语言。想法很简单：1- 捕获整个登录网页，2- 更改 action，3- 添加用户名和inputs 的密码，然后 4- 以编程方式单击提交按钮。这是带有 4 个步骤的 PHP 代码（特定于 OP 想要的网站）：

▬▬1▬▬
$page = file_get_contents( "http://powerschool.fortschools.org/public" );

▬▬2▬▬
$page = str_replace( 'action="/guardian/home.html"',
       'action="https://powerschool.fortschools.org/guardian/home.html"',
                     $page );

▬▬3▬▬
$page = str_replace(
'<input type="text" id="fieldAccount" name="account" value="" size="39" />',
'<input type="text" id="fieldAccount" name="account" value="■█■█■" size="39" />',
                     $page );

$page = str_replace(
'<input type="password" id="fieldPassword" name="pw" value="" size="39" autocomplete="new-password" />',
'<input type="password" id="fieldPassword" name="pw" value="■█■█■" size="39" autocomplete="new-password" />',
                    $page );

▬▬4▬▬
echo "$page
      <script>
       document.getElementById('btn-enter-sign-in').click();
      </script>";

■█■█■ 代表用户名和密码。

我无法使用它登录，因为它不允许我创建一个帐户来测试它（它会询问该学校儿童的 ID），但我已使用此代码以编程方式进入其他网站。< /p>

顺便说一下，必须更改 action 才能在本地运行此代码（是的，从 localhost 运行效果很好）。

如何以编程方式登录网站？

2 个答案: