查询应该更改

时间:2014-01-19 04:33:07

标签: sql sql-server-2008 date

我有一个查询,此查询显示将基于当天所显示的那一天的当天。

在此时间表中,我的开始日期和结束日期从2014-01-06 2014-01-12一周开始..

例如:

declare @Hours as Table ( EmpId Int, Monday Time, Tuesday Time, Wednesday Time,
  Thursday Time, Friday Time, Saturday Time, Sunday Time, StartDate Date, EndDate Date );
insert into @Hours
  ( EmpId, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday, StartDate, EndDate )
  values
  ( 1, '08:00', '00:00', '00:00', '00:00', '00:00', '00:00', '00:00', '2014-01-06 00:00:00.000', '2014-01-12 00:00:00.000' );
select * from @Hours;


with Week as (
  -- Build a table of all of the dates in the work week.
  select StartDate as WorkDate, EndDate
    from @Hours
  union all
  select DateAdd( day, 1, WorkDate ), EndDate
    from Week
    where WorkDate < EndDate ),
  DaysHours as (
  -- Build a table of the hours assigned to each date.
  select EmpId,
    case DatePart( weekday, W.WorkDate )
      when 1 then H.Monday
      when 2 then H.Tuesday
      when 3 then H.Wednesday
      when 4 then H.Thursday
      when 5 then H.Friday
      when 6 then H.Saturday
      when 7 then H.Sunday
      end as Hours,
    WorkDate as StartDate, WorkDate as EndDate
    from Week as W inner join
      @Hours as H on H.StartDate <= W.WorkDate and W.WorkDate <= H.EndDate )
  -- Output the non-zero hours.
  select EmpId, Hours,StartDate as StartDate, EndDate
    from DaysHours
    where Hours <> Cast( '00:00' as Time );

需要像这样的输出:

EmpId       Hours            StartDate  EndDate
----------- ---------------- ---------- ----------
1           08:00:00.0000000 2014-01-06 2014-01-06

因为星期一我们只有值。但我的输出就像这样

EmpId       Hours            StartDate  EndDate
----------- ---------------- ---------- ----------
1           08:00:00.0000000 2014-01-12 2014-01-12

它应该根据价值在哪一天起作用。

任何正文都可以在此查询中自行更改。

谢谢,

2 个答案:

答案 0 :(得分:0)

执行后

EmpId   Hours               StartDate   EndDate
1       08:00:00.0000000    2014-01-06  2014-01-06

MS SQL Server 2008 R2

答案 1 :(得分:0)

尝试此查询:

SELECT  x.EmpId, ca.Hours, ca.CurrentDate AS StartDate, ca.CurrentDate AS EndDate
FROM    @Hours x
CROSS APPLY 
(
    SELECT  y.Hours, DATEADD(DAY, y.NumOfDays, x.StartDate)
    FROM 
    (
        SELECT x.Monday, 0
        UNION ALL SELECT x.Tuesday, 1
        UNION ALL SELECT x.Wednesday, 2
        UNION ALL SELECT x.Thursday, 3
        UNION ALL SELECT x.Friday, 4
        UNION ALL SELECT x.Saturday, 5
        UNION ALL SELECT x.Sunday, 6
    ) y (Hours, NumOfDays)
    WHERE y.Hours <> '00:00:00.0000000'
) ca (Hours, CurrentDate);
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