c ++中文件处理错误 - 没有匹配函数来调用`std :: basic_fstream <char,std :: char_traits <char =“”>&gt; :: open(const char [8],bool)'</char ,>

时间:2014-01-20 03:40:10

标签: c++

我正在尝试一个文件处理程序来输入记录,而在另一个程序中尝试删除一条记录。我似乎得到了这个错误 -

没有匹配函数来调用`std :: basic_fstream&gt; :: open(const char [8],bool)'

对于每个f.open语句都有一个ios :: binary声明。

这是代码

这个用于输入记录

#include<iostream.h>
#include<fstream.h>

class employee
{
      int code;
      char name[20];
      char desig[15];
      float salary;

      public: void get_emp();
};

void employee:: get_emp()
{
     cout<<"Code--> ";
     fflush(stdin);
     cin>>code;
     cout<<"Name--> ";
     fflush(stdin);
     gets(name);
     cout<<"Designation--> ";
     fflush(stdin);
     gets(desig);
     cout<<"Salary--> ";
     fflush(stdin);
     cin>>salary;
}

int main()
{
    fstream f;
    char ch;
    f.open("EMP.dat", ios::binary||ios::app);
    employee emp;
    cout<<"Enter data:\n";
    do
    {
                 emp.get_emp();
                 f.write((char*)&emp,sizeof(emp));
                 cout<<"Entre more???(y/n)";
                 cin>>ch;
    }while((ch=='y')||(ch=='Y'));
    f.close();
    system("pause>null");
    return 0;
}

这是为了删除记录

#include<iostream.h>
#include<fstream.h>
#include<stdlib.h>
struct employee
{
       int code;
       char name[20];
       char desig[15];
       float salary;
}emp;

int main()
{
    int xcode; //temporary declaration for employee code
    int flag = 0;
    fstream ef, tf; 
    //ef opened for reading, tf opened for transferring all records including modified      record 
    ef.open("EMP.dat", ios::binary|| ios::in);
    tf.open("TEMP.dat", ios::binary|| ios::out);
    cout<<"Enter employee code to delete:";
    cin>>xcode;
    while(ef)
    {
             if(!ef)
                exit(0);
             ef.read((char*)&emp, sizeof(emp));
             if(emp.code == xcode)
             {
                            flag = 1;
             }
             else
                tf.write((char*)&emp, sizeof(emp));
    }
    ef.close();
    tf.close();
    if(flag == 1)
       cout<<"Record deleted.";
    else
       cout<<"Not found.";
    fstream xf, yf;
    //tf opened for reading
    xf.open("TEMP.dat", ios::binary||ios::in);
    //ef opened for copying all records from TEMP.dat
    yf.open("EMP.dat",ios::binary||ios::out);
    while(xf)
    {
             if(!xf)
                exit(0);
             xf.read((char*)&emp, sizeof(emp));
             yf.write((char*)&emp, sizeof(emp));
    }
    xf.close();
    yf.close();
    system("pause");
    return 0;
}

请帮忙。我的考试需要它。

谢谢

1 个答案:

答案 0 :(得分:3)

按位OR是单个管道(|),而不是双管道。