Sql Server:每十分钟间隔计算记录(包括零)

时间:2010-01-24 02:07:45

标签: sql-server sql-server-2005

我目前有一个表(SQL Server 2005),它记录了我的Web应用程序的访问,我想整理一些代码来报告(并显示该流量的可视化)。我想要的是显示过去24小时内每十分钟间隔内的访问次数。

我有一个查询可以做到这一点,但有十分钟的间隔期间没有访问,我想调整我的查询以显示这些间隔的零计数。我想我可以使用游标来提出一些东西,但如果我能避免它,我宁愿不使用它们。

以下是目前的查询:

DECLARE @time int
DECLARE @interval int
SELECT @time=96
SELECT @interval=10
SELECT interval,
COUNT(*) AS requestCount,
DATEDIFF(MINUTE,DATEADD(HOUR,-1*@time-1,getDate()),interval)/@interval AS intervalPos
FROM 
(SELECT DATEADD(MINUTE, FLOOR(DATEDIFF(MINUTE, getDate(), requestBegin) / (@interval*1.0)) * @interval,getDate())
FROM [track_pageSubmit] WHERE requestBegin IS NOT NULL AND DATEDIFF(HOUR,requestBegin,getDate()) < @time) AS I(interval) 
GROUP BY interval ORDER BY interval

这是表结构:

CREATE TABLE [dbo].[Track_PageSubmit](
    [id] [int] IDENTITY(1,1) NOT NULL,
    [popid] [int] NOT NULL,
    [section] [varchar](30) NULL,
    [page] [int] NULL,
    [requestBegin] [datetime] NULL,
    [requestEnd] [datetime] NULL,
    [rendered] [datetime] NULL,
    [postBegin] [datetime] NULL,
    [postEnd] [datetime] NULL
)

以下是一些记录的样子:

INSERT INTO track_pageSubmit (popid,section,page,requestbegin,requestend,rendered,postbegin,postend)
SELECT '2393712','Main_Can_Eng','10','2010-01-22 10:22:08.287','2010-01-22 10:22:08.330',NULL,'2010-01-22 10:22:09.503','2010-01-22 10:22:09.627' UNION
SELECT '2393712','Main_Can_Eng','11','2010-01-22 10:22:09.660','2010-01-22 10:22:09.770',NULL,'2010-01-22 10:22:10.973','2010-01-22 10:22:11.050' UNION
SELECT '2393712','Main_Can_Eng','12','2010-01-22 10:22:11.080','2010-01-22 10:22:11.143',NULL,'2010-01-22 10:22:12.503','2010-01-22 10:22:12.567' UNION
SELECT '2394478','main','21','2010-01-21 10:38:54.057','2010-01-21 10:38:54.117','2010-01-21 10:38:54.487','2010-01-21 10:38:55.633','2010-01-21 10:38:55.697' UNION
SELECT '2394478','main','22','2010-01-21 10:38:55.757','2010-01-21 10:38:55.820','2010-01-21 10:38:56.197','2010-01-21 10:38:57.477','2010-01-21 10:38:57.570' UNION
SELECT '2394478','main','23','2010-01-21 10:38:57.617','2010-01-21 10:38:57.993','2010-01-21 10:38:58.367','2010-01-21 10:38:59.397','2010-01-21 10:38:59.493' UNION
SELECT '2394478','main','25','2010-01-21 10:38:59.553','2010-01-21 10:38:59.617','2010-01-21 10:38:59.993','2010-01-21 10:39:01.227','2010-01-21 10:39:01.303' UNION
SELECT '2394478','main','26','2010-01-21 10:39:01.350','2010-01-21 10:39:01.477','2010-01-21 10:39:01.860','2010-01-21 10:39:02.787','2010-01-21 10:39:02.867' UNION
SELECT '2394478','main','27','2010-01-21 10:39:02.930','2010-01-21 10:39:03.007','2010-01-21 10:39:03.400','2010-01-21 10:39:04.147','2010-01-21 10:39:04.460' UNION
SELECT '2394478','main','28','2010-01-21 10:39:04.507','2010-01-21 10:39:05.147','2010-01-21 10:39:05.790','2010-01-21 10:39:19.413','2010-01-21 10:39:19.477' UNION
SELECT '2393754','exp46_cex','1','2010-01-22 12:40:56.563','2010-01-22 12:40:56.640',NULL,'2010-01-22 12:40:58.657','2010-01-22 12:40:58.733' UNION
SELECT '2393754','exp46_cex','2','2010-01-22 12:40:58.750','2010-01-22 12:40:58.780',NULL,'2010-01-22 12:41:15.623','2010-01-22 12:41:15.657' UNION
SELECT '2393754','additionalComments','1','2010-01-22 12:41:15.670','2010-01-22 12:41:15.733',NULL,'2010-01-22 12:41:19.000','2010-01-22 12:41:19.030' UNION
SELECT '2393802','main','2','2010-01-22 12:44:50.857','2010-01-22 12:44:50.933',NULL,'2010-01-22 12:44:53.497','2010-01-22 12:44:53.557' UNION
SELECT '2393802','main','3','2010-01-22 12:44:53.590','2010-01-22 12:44:53.667',NULL,'2010-01-22 12:44:56.370','2010-01-22 12:44:56.730'

奖励积分(以我的额外感谢的形式)给任何可以更改查询的人,以便我还可以每个时间间隔报告不同的popid(除了总请求)。

谢谢!

4 个答案:

答案 0 :(得分:4)

- 因为您的样本数据跨越27小时:

DECLARE
    @hours TINYINT,
    @minute_interval TINYINT,
    @start SMALLDATETIME;

SELECT
    @hours = 27,
    @minute_interval = 10,
    @start = '20100122 13:00';

;WITH x AS 
(
    SELECT TOP (@hours * (60 / @minute_interval))
        n = ROW_NUMBER() OVER
        (ORDER BY column_id)
    FROM msdb.sys.columns
),
intervals(boundary) AS
(
    SELECT CONVERT
    (
      SMALLDATETIME,
      DATEADD(MINUTE, (-n * @minute_interval), @start)
    )
    FROM x
)
SELECT
    i.boundary,
    RequestCount = COUNT(d.id),
    DistinctPopIDs = COUNT(DISTINCT d.popid)
FROM
    intervals AS i
LEFT OUTER JOIN
    dbo.Track_PageSubmit AS d
    ON d.requestBegin >= i.boundary
    AND d.requestBegin < DATEADD(MINUTE, @minute_interval, i.boundary)
GROUP BY i.boundary
ORDER BY i.boundary;

答案 1 :(得分:2)

这样做的简单方法是使用CTE并使用开始时间间隔创建一个辅助表,然后使用两者之间加入主查询中的该表。

这有意义吗?我将稍微研究一些示例代码。

DECLARE @time int
DECLARE @interval int
SELECT @time=96
SELECT @interval=10

DECLARE @count int
SELECT @count=1

;WITH daterange AS
(
   SELECT 1 as [id], Max(requestbegin) as maxr, Min(requestBegin) as minr
   FROM track_pagesubmit
), intervals as
(
   SELECT @count AS interval, minr as intervalpos
   FROM daterange
   WHERE [id] = 1
   UNION ALL
   SELECT interval+1 AS interval,
          DATEADD(MINUTE,@interval,intervalpos) as intervalpos
   FROM intervals
   JOIN daterange on [ID] = 1
   WHERE DATEADD(MINUTE,@interval,intervalpos) < maxr
)
SELECT interval, intervalpos, 
       COUNT(DISTINCT track_pagesubmit.popid) as popcount,
       COUNT(track_pagesubmit.id AS requestcount 
FROM intervals
LEFT JOIN track_pagesubmit ON requestbegin IS NOT NULL 
  AND requestBegin BETWEEN intervalpos AND DATEADD(ns,-1,DATEADD(MINUTE,@interval,intervalpos))
GROUP BY interval, intervalpos 
OPTION (MAXRECURSION 200)

答案 2 :(得分:0)

递归CTE似乎总是优于数字表,但传统上使用both methods

答案 3 :(得分:0)

这有点粗糙,但应该适合你:

WITH Nbrs_2( n ) AS ( SELECT 1 UNION SELECT 0 ),
    Nbrs_1( n ) AS ( SELECT 1 FROM Nbrs_2 n1 CROSS JOIN Nbrs_2 n2 ),
    Nbrs_0( n ) AS ( SELECT 1 FROM Nbrs_1 n1 CROSS JOIN Nbrs_1 n2 ),
    Nbrs  ( n ) AS ( SELECT 1 FROM Nbrs_0 n1 CROSS JOIN Nbrs_0 n2 )
select n.n as TenMinuteInterval, count(case when t.requestBegin is null then null else 1 end) as Count
from (
    SELECT n - 1 as n
    FROM (SELECT ROW_NUMBER()  OVER (ORDER BY n)
    FROM Nbrs) D ( n )
    WHERE n <= 144
) n
left outer join track_pageSubmit t on n.n = floor((cast(requestBegin - convert(int, requestBegin) as decimal(10,3)) % 1) * 144) 
    and requestBegin between '2010-01-21' and '2010-01-22'
group by n.n

输出:

TenMinuteInterval Count
-----------------------
0                  0
1                  0
2                  0
3                  0
4                  0
5                  0
6                  0
7                  0
8                  0
9                  0
10                 0
11                 0
12                 0
13                 0
14                 0
15                 0
16                 0
17                 0
18                 0
19                 0
20                 0
21                 0
22                 0
23                 0
24                 0
25                 0
26                 0
27                 0
28                 0
29                 0
30                 0
31                 0
32                 0
33                 0
34                 0
35                 0
36                 0
37                 0
38                 0
39                 0
40                 0
41                 0
42                 0
43                 0
44                 0
45                 0
46                 0
47                 0
48                 0
49                 0
50                 0
51                 0
52                 0
53                 0
54                 0
55                 0
56                 0
57                 0
58                 0
59                 0
60                 0
61                 0
62                 0
63                 7
64                 0
65                 0
66                 0
67                 0
68                 0
69                 0
70                 0
71                 0
72                 0
73                 0
74                 0
75                 0
76                 0
77                 0
78                 0
79                 0
80                 0
81                 0
82                 0
83                 0
84                 0
85                 0
86                 0
87                 0
88                 0
89                 0
90                 0
91                 0
92                 0
93                 0
94                 0
95                 0
96                 0
97                 0
98                 0
99                 0
100                0
101                0
102                0
103                0
104                0
105                0
106                0
107                0
108                0
109                0
110                0
111                0
112                0
113                0
114                0
115                0
116                0
117                0
118                0
119                0
120                0
121                0
122                0
123                0
124                0
125                0
126                0
127                0
128                0
129                0
130                0
131                0
132                0
133                0
134                0
135                0
136                0
137                0
138                0
139                0
140                0
141                0
142                0
143                0
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