Question

如何根据批处理文件中的当前日期获取上周日日期。为了获得当前日期，我正在使用此...

echo %date:~-3,2%\%date:~7,2%\%date:~10,4%

Answer 1

@if (@x)==(@y) @end /***** jscript comment ******
@echo off
for /f "delims=" %%d in ('cscript //E:JScript //nologo "%~f0"') do set "p_sund=%%d"
echo %p_sund%
exit /b 0
*****  end comment *********/
var beforeOneWeek = new Date(new Date().getTime() - 60 * 60 * 24 * 7 * 1000)
  , day = beforeOneWeek.getDay()
  , diffToMonday = beforeOneWeek.getDate() - day + (day === 0 ? -6 : 1)
  , lastMonday = new Date(beforeOneWeek.setDate(diffToMonday))
  , lastSunday = new Date(beforeOneWeek.setDate(diffToMonday + 6));

  WScript.Echo(beforeOneWeek);

Borrowed some code from here.

编辑如果禁用了Windows脚本宿主exe，则使用mshta cab：

@if (@x)==(@y) @end /***** jscript comment ******
@echo off
for /f "delims=" %%d in ('cscript //E:JScript //nologo "%~f0"') do set "p_sund=%%d"
rem echo %p_sund%
Echo ^<html^>^<head^>>"temp.hh"
Echo ^<hta:application windowstate="minimize"^>>>"temp.hh"
Echo ^<script type="text/jscript" src="%~nx0"^>>>"temp.hh"
Echo ^</script^>^</head^>^</html^>>>"temp.hh"

Mshta.exe "temp.hh"
type temp.res

del /q /f "temp.hh" ""temp.res"" >nul 2>&1


exit /b 0
*****  end comment *********/
var beforeOneWeek = new Date(new Date().getTime() - 60 * 60 * 24 * 7 * 1000)
  , day = beforeOneWeek.getDay()
  , diffToMonday = beforeOneWeek.getDate() - day + (day === 0 ? -6 : 1)
  , lastMonday = new Date(beforeOneWeek.setDate(diffToMonday))
  , lastSunday = new Date(beforeOneWeek.setDate(diffToMonday + 6));

  WScript.Echo(beforeOneWeek);

  var objFSO=new ActiveXObject("Scripting.FileSystemObject");
  var outFile="temp.res";
  var objFile = objFSO.CreateTextFile(outFile,true);
  objFile.Write(beforeOneWeek);
  objFile.Close();

稍后会考虑PowerShell解决方案。

从当前日期获取上周日日期

1 个答案: