如何从FacebookApiException $e获取代码ID？
我正在使用Facebook发帖。但有时它无法发布内容。我在下面使用这些代码，我在数组$e中找到错误响应代码id，但是它们都受到保护，那我怎么能得到代码？
try{
$facebook->setAccessToken($access_token);
$rs= $facebook->api('/me/feed','POST',$post_data);
} catch (FacebookApiException $e) {
print_r($e);
}
然后我收到错误信息：
FacebookApiException Object
(
[result:protected] => Array
(
[error] => Array
(
[message] => Invalid OAuth access token.
[type] => OAuthException
[code] => 190 // I need this code
)
)
[message:protected] => Invalid OAuth access token.
[string:private] =>
[code:protected] => 0
[file:protected] => D:\phpnow\htdocs\laji\facebook-php-sdk\base_facebook.php
[line:protected] => 1267
[trace:private] => Array
(
[0] => Array
(
[file] => D:\phpnow\htdocs\laji\facebook-php-sdk\base_facebook.php
[line] => 876
[function] => throwAPIException
[class] => BaseFacebook
[type] => ->
[args] => Array
(
[0] => Array
(
[error] => Array
(
[message] => Invalid OAuth access token.
[type] => OAuthException
[code] => 190
)
)
)
)
[1] => Array
(
[file] => D:\phpnow\htdocs\laji\facebook-php-sdk\base_facebook.php
[line] => 650
[function] => _graph
[class] => BaseFacebook
[type] => ->
[args] => Array
(
[0] => /me/feed
[1] => POST
[2] => Array
(
[access_token] => 1CAACg13jYHp8BAP0QEOK8PwC7ZCMnSa1tAQclbRJpcNP1zQIBnB1to6etQ2wb8wiVcETDvT5dRZAUiNiZBFvt1RYgo5xUe1do4yeY5DxKIjjDBbElI8zZBBlz5yHRwigIcNYtyhHY9ZAtHL16ZAMPyo43wZANhGWE6o6EV7hXZBtxBEN24xTlGa7M
[picture] => http://imgjy.com/FPB470/m/5236e26acc73a.jpg
[link] => http://www.persunmall.com/persun/giveaway02.html?refer_id=1900
[name] => my all_prams link <name>7458
)
)
)
[2] => Array
(
[file] => D:\phpnow\htdocs\laji\fb_post.php
[line] => 98
[function] => api
[class] => BaseFacebook
[type] => ->
[args] => Array
(
[0] => Array
(
[0] => Facebook Object
(
[sharedSessionID:protected] =>
[appId:protected] => 176847305842335
[appSecret:protected] => f79311ddff5888a165d46159b06f4670
[user:protected] =>
[signedRequest:protected] =>
[state:protected] =>
[accessToken:protected] =>
[fileUploadSupport:protected] =>
[trustForwarded:protected] =>
)
[1] => _graph
)
[1] => Array
(
[0] => /me/feed
[1] => POST
[2] => Array
(
[access_token] => 1CAACg13jYHp8BAP0QEOK8PwC7ZCMnSa1tAQclbRJpcNP1zQIBnB1to6etQ2wb8wiVcETDvT5dRZAUiNiZBFvt1RYgo5xUe1do4yeY5DxKIjjDBbElI8zZBBlz5yHRwigIcNYtyhHY9ZAtHL16ZAMPyo43wZANhGWE6o6EV7hXZBtxBEN24xTlGa7M
[picture] => http://imgjy.com/FPB470/m/5236e26acc73a.jpg
[link] => http://www.persunmall.com/persun/giveaway02.html?refer_id=1900
[name] => my all_prams link <name>7458
)
)
)
)
)
)
答案 0 :(得分：0)
没有尝试过，这不会起作用吗？
echo "Code: " . $e["error"]["code"];
答案 1 :(得分：0)
我在您的查询中理解的是您想要代码ID，即 [code] =＆gt; 190
看到这里我们正在使用 FacebookApiException 类
有以下方法
**[0] => __construct
[1] => getResult
[2] => getType
[3] => __toString
[4] => getMessage
[5] => getCode
[6] => getFile
[7] => getLine
[8] => getTrace
[9] => getPrevious
[10] => getTraceAsString**
so from your code
try{
$facebook->setAccessToken($access_token);
$rs= $facebook->api('/me/feed','POST',$post_data);
} catch (FacebookApiException $e) {
print_r($e);
}
as per your code
you can do two thing
1.
try{
$facebook->setAccessToken($access_token);
$rs= $facebook->api('/me/feed','POST',$post_data);
} catch (FacebookApiException $e) {
echo $e->getCode(); //which is the 5th method of the class
}
or you can simply get all response like
2.
try{
$facebook->setAccessToken($access_token);
$rs= $facebook->api('/me/feed','POST',$post_data);
} catch (FacebookApiException $e) {
$result = $e->getResult(); //which is the 1st method of the class and provide you all response
//so for getting the code only
echo $result['error']['code'];
}
希望这会对你有所帮助
答案 2 :(得分：0)
根据facebook doc。我不确定这是否有帮助。
$result = $e->getResult();
error_log(json_encode($result));
请关注：https://developers.facebook.com/docs/reference/php/exception-getResult