Question

我有登录我网站的代码但当我用用户名和密码登录时，我得到空白页面我使用linux服务器 - fedora- 我是从终端

创建数据库和导入表

这是我的页面表格

<html>
<head>
<body background="se16.jpg">
<form method="post" action="w.php">
<center>
<br>
<h1> <p style="color:brown;">  Login Page </p> </h1> 

<hr color="brown"> <br> 
<caption><h1><p style="color:black;">please Enter Username & Password</p></h1><caption>
<table border="3">

<tr><td><h2><p style="color:black;">Username: </p></td><td><input type="text" name="username" /></td><h2></tr>

<tr><td><h2><p style="color:black;">Password:</p> </td><td><input type="password"     name="password" /></td></h2></tr>


<tr><td></td><td><input type="submit" value="Log in" /></td></tr>

</table>
</center>
</form>
</body>
</html>

和查询的php页面是

<?php
session_start();
 echo "username: " . $_POST['username'];
 echo "<br>";
 echo "Password: " . $_POST['password'];
 echo "<br>";
include("connect.php");

// Pass Query
$query="SELECT username AND password FROM login ";

// Execute Query
$result = mysql_query($query) or die ("error in query:$query.".mysql_query());
echo $result;
echo "<br>";
$username=$_POST['username']; 
$password=$_POST['password'];

if(mysql_num_rows($result)>0)
{
echo "ssss";
 while($row=mysql_fetch_assoc($result))
 {
    $sql="SELECT * FROM login WHERE username='$username' AND password='$password'";
    $result=mysql_query($sql) or die ("error in query:$query.".mysql_query());
    $count=mysql_num_rows($result);

if($count == 1)
{
$query1="SELECT username FROM login WHERE password='$password'";
$result = mysql_query($query1)or die ("error in query:$query.".mysql_query());
while($row=mysql_fetch_assoc($result))
 {
  $username=$row['username'];
 }
 $flag=true;
 break;
 }
 }
}
else
    {
        echo 'No Data Found';
   }

  if($flag==true)
 {
    $data = mysql_fetch_object(mysql_query("SELECT * FROM login WHERE username='$username' AND password='$password'"));
$_SESSION['valid_user'] = $data->id;
    echo '<div align="left"><font color="#6666CC"> Welcome </font><font color="#FF6600">'.$username.'</font></div>';
echo '<div align="right"><a href="logout.php">Log Out</a></div>';
include("main1.php");
   }
  else
 {
include("log1.html");
  }

    // mysql_close($con);
  ?>

如果我使用此代码

     echo "username: " . $_POST['username'];
     echo "<br>";
     echo "Password: " . $_POST['password'];
     echo "<br>";

我得到用户名和密码coorect

并连接.php文件

<?php
$host      ="localhost";
$username  ="root";
$password  ="MyS12345";
$db_name   ="jointdb";
$conn = mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

?>

Answer 1

首先查询不正确

$query="SELECT username AND password FROM login ";

应该是

$query="SELECT username,password FROM login ";

在connect.php中，正确的代码是

$host ="localhost"; 
$username ="root"; 
$password ="MyS12345"; 
$db_name ="jointdb"; 
$conn = mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB");

注意：不推荐使用mysql_ *函数，因此请开始学习mysqli_ *函数或PDO。

登录时的空白页面

1 个答案: