如何在没有persistence.xml的情况下配置Spring?

时间:2014-01-27 13:17:37

标签: java spring hibernate jpa configuration

我正在尝试设置spring xml配置,而不必创建更进一步的persistence.xml。但是我经常遇到以下异常,即使我在spring.xml

中包含了数据库属性
    Exception in thread "main" org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in file [C:\Users\me\workspace\app\src\main\webapp\WEB-INF\applicationContext.xml]: Invocation of init method failed; nested exception is java.lang.IllegalStateException: No persistence units parsed from {classpath*:META-INF/persistence.xml}

spring.xml:

  <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
    <property name="driverClassName" value="${jdbc.driverClassName}" />
    <property name="url" value="${jdbc.url}" />
    <property name="username" value="${jdbc.username}" />
    <property name="password" value="${jdbc.password}" />
  </bean>

    <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="dataSource" />
     <property name="jpaProperties">
         <props>
            <prop key="hibernate.dialect">${hibernate.dialect}</prop>
            <prop key="hibernate.hbm2ddl.auto">${hibernate.hbm2ddl.auto}</prop>
            <prop key="hibernate.show_sql">${hibernate.show_sql}</prop>
            <prop key="hibernate.format_sql">${hibernate.format_sql}</prop>
         </props>
      </property>
    </bean>

我在这里缺少什么?

4 个答案:

答案 0 :(得分:41)

来自Spring Guide Accessing Data with JPA

@Configuration
@EnableJpaRepositories
public class Application {

    @Bean
    public DataSource dataSource() {
        return new EmbeddedDatabaseBuilder().setType(H2).build();
    }

    @Bean
    public LocalContainerEntityManagerFactoryBean entityManagerFactory(DataSource dataSource, JpaVendorAdapter jpaVendorAdapter) {
        LocalContainerEntityManagerFactoryBean lef = new LocalContainerEntityManagerFactoryBean();
        lef.setDataSource(dataSource);
        lef.setJpaVendorAdapter(jpaVendorAdapter);
        lef.setPackagesToScan("hello");
        return lef;
    }

    @Bean
    public JpaVendorAdapter jpaVendorAdapter() {
        HibernateJpaVendorAdapter hibernateJpaVendorAdapter = new HibernateJpaVendorAdapter();
        hibernateJpaVendorAdapter.setShowSql(false);
        hibernateJpaVendorAdapter.setGenerateDdl(true);
        hibernateJpaVendorAdapter.setDatabase(Database.H2);
        return hibernateJpaVendorAdapter;
    }

Spring Boot

启用Spring Boot应用程序后,这更容易:

示例application.yaml

spring:
    datasource:
        url: jdbc:h2:mem:test
        username: sa
        password: sa
        driver-class-name: org.h2.Driver
    jpa:
        database: H2
        show-sql: false
        hibernate:
            format_sql: true
            ddl-auto: auto

答案 1 :(得分:28)

指定“packagesToScan”&amp; entityManagerFactory bean定义中的“persistenceUnitName”属性。

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="dataSource" />

        <property name="persistenceUnitName" value="myPersistenceUnit" />
        <property name="packagesToScan" >
            <list>
                <value>org.mypackage.*.model</value>
            </list>
        </property>

        <property name="jpaProperties">
            <props>
                <prop key="hibernate.dialect">${hibernate.dialect}</prop>
                <prop key="hibernate.hbm2ddl.auto">${hibernate.hbm2ddl.auto}</prop>
                <prop key="hibernate.show_sql">${hibernate.show_sql}</prop>
                <prop key="hibernate.format_sql">${hibernate.format_sql}</prop>
            </props>
        </property>
    </bean>

请注意,这是针对Spring版本&gt; 3.1

答案 2 :(得分:3)

MariuszS&#39;答案是好的,除了entityManagerFactory方法应该返回EntityManagerFactory。要做到这一点,可以这样写:

@Bean
public EntityManagerFactory entityManagerFactory(DataSource dataSource, JpaVendorAdapter jpaVendorAdapter) {
    LocalContainerEntityManagerFactoryBean lef = new LocalContainerEntityManagerFactoryBean();
    lef.setDataSource(dataSource);
    lef.setJpaVendorAdapter(jpaVendorAdapter);
    lef.setPackagesToScan("hello");
    return lef.object();
}

对于未来的受众:以下代码有效:

@Bean (name = "entityManagerFactory")
public EntityManagerFactory entityManagerFactory(DataSource dataSource, JpaVendorAdapter jpaVendorAdapter)
{
    LocalContainerEntityManagerFactoryBean lef = new LocalContainerEntityManagerFactoryBean();
    lef.setDataSource(dataSource);
    lef.setJpaVendorAdapter(jpaVendorAdapter);
    lef.setPackagesToScan("*.models*");
    lef.afterPropertiesSet(); // It will initialize EntityManagerFactory object otherwise below will return null
    return lef.getObject();
}

答案 3 :(得分:2)

假设您有PersistenceProvider实施(例如org.hibernate.jpa.HibernatePersistenceProvider),您可以使用PersistenceProvider#createContainerEntityManagerFactory(PersistenceUnitInfo info, Map map)方法引导EntityManagerFactory而无需persistence.xml

然而,你必须实现PersistenceUnitInfo接口很烦人,所以你最好使用Spring或Hibernate,它们都支持在没有persistence.xml文件的情况下引导JPA:

this.nativeEntityManagerFactory = provider.createContainerEntityManagerFactory(
    this.persistenceUnitInfo, 
    getJpaPropertyMap()
);

PersistenceUnitInfo类由特定于Spring的MutablePersistenceUnitInfo类实现。

查看this article,了解如何使用Hibernate实现这一目标。