Question

我在这里遵循本指南tango with django，我正在阅读/复制tutorial part 3

但我无法获得不同的观点来展示不同的内容。我错过了/某种地方的解释。

所以这是我的项目urls.py

from django.conf.urls import patterns, include, url

# Uncomment the next two lines to enable the admin:
# from django.contrib import admin
# admin.autodiscover()

urlpatterns = patterns('',
    # Examples:
    # url(r'^$', 'Sayth.views.home', name='home'),
    # url(r'^Sayth/', include('Sayth.foo.urls')),

    # Uncomment the admin/doc line below to enable admin documentation:
    # url(r'^admin/doc/', include('django.contrib.admindocs.urls')),

    # Uncomment the next line to enable the admin:
    # url(r'^admin/', include(admin.site.urls)),
    url(r'^rango/', include('rango.urls')),
    url(r'^rango/about/', include('rango.urls')),
)

这是我的应用程序urls.py

from django.conf.urls import patterns, url
from rango import views

urlpatterns = patterns('',
            url(r'^$', views.index, name='index'),
            url(r'^$', views.about, name='about'),
            )

这些是我的观点

# Create your views here.
from django.http import HttpResponse

def index(request):
    return HttpResponse("Rango says Hello World! <a href='/rango/about'>About</a>" )

def about(request):
    return HttpResponse("This is the about page. <a href='/rango/'>Index</a>")

我的两个页面都解析但都显示索引页面，为什么？

Answer 1

定义的网址不正确。根urls.py应该只有一个指向应用程序的指针，应用程序的urls.py应该解析不同的端点。

尝试以下urls.py：

#Project urls.py
from django.conf.urls import patterns, include, url
urlpatterns = patterns('',
    # Examples:
    # url(r'^$', 'Sayth.views.home', name='home'),
    # url(r'^Sayth/', include('Sayth.foo.urls')),

    # Uncomment the admin/doc line below to enable admin documentation:
    # url(r'^admin/doc/', include('django.contrib.admindocs.urls')),

    # Uncomment the next line to enable the admin:
    # url(r'^admin/', include(admin.site.urls)),
    url(r'^rango/', include('rango.urls')),
)


#rango/urls.py
from django.conf.urls import patterns, url
from rango import views

urlpatterns = patterns('',
            url(r'^$', views.index, name='index'),
            url(r'^about/$', views.about, name='about'),
            )

Answer 2

正如第一个回答所提到的，你的项目的urls.py只需要一个指向应用程序urls.py的指针。

从概念上讲，就像这样，任何匹配'^ rango /'的东西都应传递到应用程序urls.py，然后应用程序处理其余的url ..'/'或'about /'

因此，在您的应用程序urls.py中，您需要确保存在每种模式的映射。

在tangowithdjango书中，about页面是一个练习，留给读者，但如果你有将来的问题，你可以随时检查应用程序的代码，例如：

项目urls.py:

https://github.com/leifos/tango_with_django/blob/master/tango_with_django_project/tango_with_django_project/urls.py

应用程序urls.py:

https://github.com/leifos/tango_with_django/blob/master/tango_with_django_project/rango/urls.py

Answer 3

如果您不想在应用上创建urls.py，您可以像这样进行网址映射：

urlpatterns = patterns('',
    # ...
    # most detailed urls comes first.
    url(r'^rango/about/?$', 'rango.views.about', name='about'),
    url(r'^rango/?$', 'rango.views.index', name='index'),

)

获取不同的视图以显示不同的内容

3 个答案: