如何除以另一个查询的结果

时间:2014-01-30 13:36:53

标签: sql oracle

这是一个基于上一篇文章的单独问题:

[Link] How to calculate Grand Totals when using OVER (partition by ...) using Oracle SQL

我正在使用以下Oracle SQL查询:

SELECT JOB_GROUP,
   SUM(PEOPLE) AS CURRENT_PEOPLE
   SUM(PEOPLE) / '100' AS RATIO
FROM MY_VIEW
WHERE MONTH = '01-DEC-2013'
GROUP BY ROLLUP (OB_GROUP)
ORDER BY RATIO DESC;

此查询为我提供了这样的输出..

JOB_GROUP    CURRENT_PEOPLE    RATIO
WORKER1     100                1.0
WORKER2     30                 .3
WORKER3     40                 .4
WORKER4     25                 .25
WORKER5     30                 .30
(NULL)      225                2.25

我需要能够将所有比率的总和除以job_group ='WORKER1',WORKER2,WORKER4的比率之和。例如,我们可以有5个不同的job_groups,但我只需要1,2和4的比率之和。我怀疑这是某种类型的子查询,但还没有得到正确的结果。

该等式看起来像工人1,2,4的总和(比率)/总和(比率)。 2.25 /(1.0 + .3 + .25)= .80

感谢您提供的任何帮助,

1 个答案:

答案 0 :(得分:0)

以下使用分析函数来获取worker1的数量:

select JOB_GROUP, CURRENT_PEOPLE,
       CURRENT_PEOPLE / sum(job_group = 'WORKER1' then CURRENT_PEOPLE end) over () as Ratio
from (SELECT JOB_GROUP,
             SUM(PEOPLE) AS CURRENT_PEOPLE
      FROM my_view
      WHERE MONTH = '01-DEC-2013'
      GROUP BY ROLLUP (JOB_GROUP)
     ) t
ORDER BY RATIO DESC;
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