Question

我有字符串数组。我想把这些数组放入一个数组中。我怎么能这样做？我试过这个：

char const * const fruits[3] = {
    "apple",
    "banana",
    "orange",
};

char const * const colors[3] = {
    "red",
    "green",
    "blue",
};

char * preset_configurations[3] =
{
    NULL, /* leave the first one blank so that this list is 1-based */
    &fruits,
    &colors,
};

但我得到warning: initialization from incompatible pointer type。有什么想法吗？

Answer 1

你需要一个双指针和一些consts（以及摆脱＆符号）：

char const * const * preset_configurations[3] =
{
    NULL, /* leave the first one blank so that this list is 1-based */
    fruits,
    colors
};

编辑：我想，在我发布上述内容后给出了额外的信息，您问题的最佳解决方案是：

// This will copy the characters of the words into the 3 16-byte arrays.
char fruits[3][16] = {
    "apple",
    "banana",
    "orange"
};
// Ditto.
char colors[3][16] = {
    "red",
    "green",
    "blue"
};
// This is how to point to the above.
char (*preset_configurations[3])[16] = {
    NULL, // this list is 1-based
    fruits,
    colors,
};

这样字符串不再是常量字符串（正如你所说，exec函数不需要）。

Answer 2

typedef const char const *(*cp3)[3];
cp3 preset_configurations[3] = {
    NULL,
    &fruits,
    &colors,
};
//printf("%s\n", (*preset_configurations[1])[2]);//orange

创建一个字符串数组

2 个答案: