Question

不确定我在这里失踪了......我得到的错误是...... 解析错误：语法错误， 8中的 updateMarkerLocations.php 中的意外'$ markerCount'（T_VARIABLE）

显然$ markerCount意外？以下是我的整个代码。谢谢！

<?php
include 'db_const.php';

function insertMarkerLocations()
{
$markerCount = 0;
if (isset($_POST['markerCount'])
    $markerCount = $_POST['markerCount']);

$con = mysql_connect($DB_HOST, $DB_USER, $DB_PASS );
if (!con) {
    $msg = 'Could not connect to DB to save';
    return $msg;
}
mysql_select_db($DB_NAME, $con);

$ID = $_POST['ID'];

for($i=0 ; $i < $markerCount; $i++){ 
      $index = $i;
      ++$index;
      $curMarkerID = $_POST["markerID$index"];
      $curLang = $_POST["lang$index"];
      $curLat = $_POST["lat$index"];
  // Now write the current marker details in to the db.
  $query = INSERT INTO userinfo (ID, markerID, lang, lat ) VALUES ('$ID', '$curMarkerID', '$curLang', '$curLat');
  mysql_query($query)
    or die(mysql_error());
}
$msg = "SUCCESS";
return $msg;
}

$msg = insertMarkerLocations();
echo json_encode($msg);
?>

Answer 1

这一行

if (isset($_POST['markerCount'])
    $markerCount = $_POST['markerCount']);

应该是

if (isset($_POST['markerCount']))
    $markerCount = $_POST['markerCount'];

Answer 2

末尾有一个不需要的括号

$markerCount = $_POST['markerCount']);

将其删除并替换为以下内容：

$markerCount = $_POST['markerCount'];

意外的$ markerCount（T_VARIABLE）

2 个答案: