昨天我一直在做作业，我已经完成了大部分工作，但是无法做出主要的事情。我不知道为什么它不起作用我问过其他学生，但没人知道是什么问题。基本上这个程序是一个小游戏，每个团队有18个玩家9。该程序随机给予玩家坐标和方向，他们开始移动。我基本上已经完成了这个程序，但是我对场有问题，它根本没有显示球员。 我尝试了很多东西，当测试注意到它甚至没有在我写的if语句中打印测试字符串。当我写这部分字段[i] [j] =＆amp; players [k] [0];我检查了field [i] [j]是否真的得到了x和y坐标，是的。但是在print_field类中，field [] []为null，字段为空。球员是一系列结构。 field是一个指向玩家或NULL的指针数组。
我已经尝试了所有的知识，并且无法做得更好。 这段代码有什么问题？为什么不向球场上的球员展示？
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#define LENGTH 25
#define WIDTH 25
enum direction {Right, Left, Up, Down}; /*Right = 0, Left = 1, Up = 2, Down = 3*/
void print_field();
void random_positions();
void playerdirection();
void motion();
void game();
struct player
{
char *dora;
char *team;
char *name; //string?
int x,y; //coordinates
int direction;
};
typedef struct player Player;
struct player *field[WIDTH][LENGTH];
Player players[8][1];
int main()
{
srand (time(NULL));
int i; //players 9 in each team team1 = 0 team2 = 1
players[0][0].name = "A1";
players[1][0].name = "A2";
players[2][0].name = "A3";
players[3][0].name = "A4";
players[4][0].name = "A5";
players[5][0].name = "A6";
players[6][0].name = "A7";
players[7][0].name = "A8";
players[8][0].name = "A9";
players[0][1].name = "B1";
players[1][1].name = "B2";
players[2][1].name = "B3";
players[3][1].name = "B4";
players[4][1].name = "B5";
players[5][1].name = "B6";
players[6][1].name = "B7";
players[7][1].name = "B8";
players[8][1].name = "B9";
for(i = 0; i < 9 ; i++)
{
players[i][0].team = "Team A";
players[i][1].team = "Team B";
players[i][0].dora = "Alive";
players[i][1].dora = "Alive";
}
random_positions();
playerdirection();
print_field();
motion (Player player);
print_field();
game();
return 0;
}
void random_positions()
{
int i,j,k;
int xs[17],ys[17];
for(i= 0; i<9 ; i++)
{
players[i][0].x = rand() % 25;
players[i][0].y = rand() % 25;
players[i][1].x = rand() % 25;
players[i][1].y = rand() % 25;
printf("A%d x = %d y = %d \n",i+1,players[i][0].x,players[i][0].y);
printf("B%d x = %d y = %d \n",i+1,players[i][1].x,players[i][1].y);
}
for(i = 0; i < 9 ; i++)
{
xs[i] = players[i][0].x;
xs[i+8] = players[i][1].x;
ys[i] = players[i][0].y;
ys[i+8] = players[i][1].y;
for(j = 0; j <= i ; j++)
{
//printf("j%d start\n",j);
if(i != j && xs[i] == xs[j])
{
//printf("i%d start\n",j);
if(ys[i] == ys[j])
{
return random_positions();
}
//("j%d done\n",j);
}
//printf("j%d done\n",j);
}
}
for(i = 0; i < 25; i++)
{
for(j = 0; j < 25; j++)
{
for(k = 0; k < 9; k++)
{
if(i == players[k][0].x && j == players[k][0].y)
{
field[i][j] = &players[k][0];
}
if(i == players[k][1].x && j == players[k][1].y)
{
field[i][j] = &players[k][1];
}
else field[i][j] = NULL; //I da J sheidzleba shesacvleli iyos
}
}
}
}
/*this function prints out the given state of the field*/
void print_field(){
int i,j;
printf("\n");
printf("|0 1 2 3 4 5 6 7 8 9 101112131415161718192021222324|\n"); /*just to show easier the allignment*/
for(j=0; j<WIDTH+2; j++) /*This first loop goes through row and creates them each by each*/
{
if(j == 0 || j == WIDTH +1) /*creates the upper and lower part of the field*/
for(i=0; i<LENGTH+2; i++) /*there should be space for frame so I added 2 to LENGTH in the loop*/
{
if(i==0)
printf("-");
else if(i == LENGTH+1)
printf("-\n");
else printf("--"); /*3 decimals*/
}
else
for(i=0; i<LENGTH+2; i++) /*Goes through the columns in this row and creates either frame or puts the nodeid*/
{
if(i==0)printf("|"); /*frame*/
else if(i == LENGTH+1) printf("| %d\n",(j-1)); /*frame*/
else if(field[j-1][i-1] != NULL)
{
printf("aaa");
printf("%-*s",2,(*field[j-1][i-1]).name); /*putting nodeid 3 decimals*/
}
else printf(" ");
}
}
printf("\n");
}
答案 0 :(得分：1)
您需要Player[9][2]而不是Player[8][1]。您应该初始化一个具有长度的数组，尽管您只能访问最多length - 1的索引，因为数组的索引是从0开始的。