Question

您好我的代码出现语法错误，我正在尝试将表单的结果保存到csv文件中。错误发生在$ savestring行...解析错误：语法错误，意外'，'在第24行的/home/blahblah/public_html/forms/ContactUs/includes/contact.php

我看不出自己做错了什么，有人能指出我的错误吗？

{
$customername = $_POST['CustomerName'];
$companyname = $_POST['CompanyName'];
$noemps = $_POST['NoEmps'];
$telephone = $_POST['TelephoneNo'];
$email = $_POST['EmailAddress'];
$addressline1 = $_POST['AddressLine1'];
$addressline2 = $_POST['AddressLine2'];
$addressline3 = $_POST['AddressLine3'];
$city = $_POST['City'];
$county = $_POST['County'];
$postcode = $_POST['PostCode'];
$enquiry = $_POST['Enquiry'];
$upload = $_POST['upload'];
$source = $_POST['Source'];
$quotecode = $_POST['QuoteCode'];


$fp = fopen(”ContactUs.csv”, “a”);
$savestring = $customername . “,” . $companyname . "," . $noemps . "," . $telephone .     "," . $email . ",“ . $addressline1 . "," . $addressline2 . "," . $addressline3 . "," . $city . "," . $county . "," . $postcode . "," . $enquiry . "," . $upload . "," . $source . "," .$qoutecode . "\n”;
fwrite($fp, $savestring);
fclose($fp);

Answer 1

问题是您正在尝试声明具有特殊字符（“）的字符串。
尝试改变这个：

$customername . “,” . $companyname

对此：

$customername . "," . $companyname

此外，还有三个：

1）”ContactUs.csv”, “a” =＆gt; "ContactUs.csv", "a"

2）$email . ",“ . $addressline1 =＆gt; $email . "," . $addressline1

3）" .$qoutecode . "\n” =＆gt; " .$qoutecode . "\n"

因此，您的新代码将是：

{
$customername = $_POST['CustomerName'];
$companyname = $_POST['CompanyName'];
$noemps = $_POST['NoEmps'];
$telephone = $_POST['TelephoneNo'];
$email = $_POST['EmailAddress'];
$addressline1 = $_POST['AddressLine1'];
$addressline2 = $_POST['AddressLine2'];
$addressline3 = $_POST['AddressLine3'];
$city = $_POST['City'];
$county = $_POST['County'];
$postcode = $_POST['PostCode'];
$enquiry = $_POST['Enquiry'];
$upload = $_POST['upload'];
$source = $_POST['Source'];
$quotecode = $_POST['QuoteCode'];


$fp = fopen("ContactUs.csv", "a");
$savestring = $customername . "," . $companyname . "," . $noemps . "," . $telephone .     "," . $email . "," . $addressline1 . "," . $addressline2 . "," . $addressline3 . "," . $city . "," . $county . "," . $postcode . "," . $enquiry . "," . $upload . "," . $source . "," .$qoutecode . "\n";
fwrite($fp, $savestring);
fclose($fp);

Answer 2

问题就在这里：

",“

你看到引号的微小差异吗？这导致第一个引用，即有效引用，保持开放。

作为旁注，你正在使用“引号”，所以默认情况下你告诉解释器解析变量的所有字符串，所以你所做的常量连接是没有意义的。只需将变量直接放入一个字符串中会很好。

Answer 3

尝试这种方式

$list = array (
    array('aaa', 'bbb', 'ccc', 'dddd'),
    array('123', '456', '789'),
    array('"aaa"', '"bbb"')
);

$fp = fopen('file.csv', 'w');

foreach ($list as $fields) {
    fputcsv($fp, $fields);
}

fclose($fp);
?>

将表单提交保存为CSV文件

3 个答案: