Spring的JDBCTemplate IllegalArgumentException:需要数据源

时间:2010-01-28 11:28:29

标签: spring derby jdbctemplate illegalargumentexception

好吧,我在配置Spring的JDBCTemplate以正常工作时遇到了问题。我试图注入数据源,但它似乎总是为空。以下是示例代码:

  1. 的applicationContext.xml:

    <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
    <property name="driverClassName" value="org.apache.derby.jdbc.EmbeddedDriver" />
    <property name="url"
        value="jdbc:derby:c:\\Derby\\MyDB\\jsfkickstart;create=true" />
    <property name="username" value="admin" />
    <property name="password" value="admin" />
    </bean>
    
    <bean id="employeeDoa" class="com.kickstart.employeeapp.doa.EmployeeDoa">
        <property name="dataSource" ref="dataSource" />
    </bean>
    
  2. 的web.xml

    <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/applicationContext.xml</param-value>
    

    <listener>
            <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <listener>
            <listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
    </listener>
    
  3. EmployeeDoa.java

    public class EmployeeDoa implements IEmployeeDoa, IDepartmentDoa {
    private DataSource dataSource;
            public List<Employee> getAllEmployees() {
            JdbcTemplate select = new JdbcTemplate(dataSource);
            return select.query(
                    "SELECT "+
                        "e.ID as empId, "+
                        "e.FIRSTNAME as empFirstName, "+ 
                        "e.LASTNAME as empLastName,  "+
                        "d.ID as depId,  "+
                        "d.NAME as depName, "+
                        "d.LOCATION as depLocation "+
                    "FROM jsfkickstart.Employee e, jsfkickstart.Department d",
                    new EmployeeMapper());
            }
    }
    
    class EmployeeMapper implements RowMapper {
        public Object mapRow(ResultSet rs, int rowNum) throws SQLException {
            Employee emp = new Employee();
            emp.setId(rs.getInt("empId"));
            emp.setFirstName(rs.getString("empFirstName"));
            emp.setLastName(rs.getString("empLastName"));
            Department dep = new Department();
            dep.setId(rs.getShort("depId"));
            dep.setLocation(rs.getString("depLocation"));
            dep.setName(rs.getString("depName"));
            emp.setDepartment(dep);
            return emp;
        }
    }
    
  4. 异常抛出:

    Exception in thread "main" java.lang.IllegalArgumentException: Property 'dataSource' is required
    at org.springframework.jdbc.support.JdbcAccessor.afterPropertiesSet(JdbcAccessor.java:134)
    at org.springframework.jdbc.core.JdbcTemplate.<init>(JdbcTemplate.java:142)
    at com.kickstart.employeeapp.doa.EmployeeDoa.addEmployee(EmployeeDoa.java:29)
    
  5. 有谁知道如何解决这个问题?如果我遗漏了问题中的任何重要信息,请告诉我。

    谢谢。

1 个答案:

答案 0 :(得分:2)

我实际上是一个非常愚蠢的例外。 setDataSource()的主体是空的,即我没有将dataSource分配给任何东西,因此它总是为空。

愚蠢的我!!!

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