Question

我有两个数组$ array1和$ array2，数据显示为：

$ ARRAY1：

Array 
  ( 
     [0] => Array 
         ( 
            [id] => 222
            [issubtask] => true 
         ) 
     [1] => Array 
         ( 
            [id] => 444
            [issubtask] => false 
         )
  )

$数组2：

Array 
  ( 
   [0] => Array 
    ( 
        [id] => 111 
        [name] => Mark 
        [isselected] => false 
        [issubtask] => false 
    ) 
   [1] => Array 
    ( 
        [id] => 222 
        [name] => Tony 
        [isselected] => false 
        [issubtask] => false 
    ) 
   [2] => Array 
    ( 
        [id] => 333 
        [name] => Jack 
        [isselected] => false 
        [issubtask] => false 
    )
   [3] => Array 
    ( 
        [id] => 444 
        [name] => Nick 
        [isselected] => false 
        [issubtask] => false 
    )   
  )

我想要做的就是从$ array1检查$ array2中匹配的'id'，然后用$ array1中'issubtask'的值替换$ array2的'issubtask'值作为'id'。< / p>

我试过了，但$ array2的值没有改变：

foreach ($array1 as $val1) {
    foreach ($array2 as $val2) {
        // Checking whether IDs match
        if ($val2['id'] == $val1['id']) {
            $val2['isselected'] = "true";
            $val2['issubtask'] = $value1['issubtask'];
        }
    }
}
print_r($array2);

我期待以下结果，但我得到了之前的$ array2值。

结果$ array2：

Array 
( 
[0] => Array 
    ( 
        [id] => 111 
        [name] => Mark 
        [isselected] => false 
        [issubtask] => false 
    ) 
[1] => Array 
    ( 
        [id] => 222 
        [name] => Tony 
        [isselected] => true 
        [issubtask] => true 
    ) 
[2] => Array 
    ( 
        [id] => 333 
        [name] => Jack 
        [isselected] => false 
        [issubtask] => false 
    )
[3] => Array 
    ( 
        [id] => 444 
        [name] => Nick 
        [isselected] => true 
        [issubtask] => false 
    )   
)

我不确定我是否采取了正确的方式。任何帮助深表感谢。
谢谢

Answer 1

您正在更改var的本地值，而不是真正存储在数组中的值。当你得到这个：

    foreach ($array2 as $key2 => $val2) {

        // This is wrong : $val2 is a local value only in the foreach
        $val2['isselected'] = "true";

        // This is ok, you really change the value in the array
        $array2[$key2]['isselected'] = true ;
    }

以下是您的问题的答案。小心使用true而不是＆＃34; true＆＃34;也。

foreach ( $array1 as $field1 )
{
    foreach ( $array2 as $key2 => $field2 ) // Note that $field2 is just a local value in this loop
    {
        if ( $field2['id'] == $field1['id'] ) // Same ID for each field, and field1 has issubtask
        {
            // You have to change the value contained in $array2[1][222], not the value stored in $field2[issubtask] because this is a local value
            $array2[$key2]['issubtask'] = $field1['issubtask'] ; // Here you have to call the "full path" of array2[$key2]
            $array2[$key2]['isselected'] = true ;
        }
    }
}

Answer 2

直接替换$ array2而不是$ val2。

foreach ($array1 as $val1) {
    foreach ($array2 as $k => $v) {
        // Checking whether IDs match
        if ($v['id'] == $val1['id']) {
            $array2[$k]['isselected'] = "true";
            $array2[$k]['issubtask'] = $val1['issubtask'];
        }
    }
}
print_r($array2);

用另一个值替换一个数组的值

2 个答案: