Question

目前该公司的空缺率为3。我希望它停止在0减去。

这是我的代码：

$result4 = mysqli_query($con,"SELECT no_of_vacancy FROM job_details WHERE jobscope= 'Information Technology' AND job_title='Oak 3 Films Pte Ltd (Sales Marketing Department)';");

$result5 = mysqli_query($con, "SELECT COUNT(company) FROM student_details WHERE jobscope1 = 'myJobScope' AND company = 'myCompany';");
while ($row5 = mysqli_fetch_assoc($result5))
{
   $result6 = mysqli_query($con, "UPDATE `job_details` SET `no_of_vacancy`= `no_of_vacancy` - 2 WHERE `job_title` = 'myCompany';"));
}

一旦学生被分配到该公司，我想从公司的空缺中减去一个值。

Company | Vacancy|

ABC     | 3

一旦有3名学生被分配，我希望它显示0。现在，每次代码运行时它都会持续到-1。

Answer 1

停止循环执行：

while ($row5 = mysqli_fetch_assoc($result5))
{
   $result6 = mysqli_query([...]);
   if(condition)
      break;
}

要跳过当前执行：

while ($row5 = mysqli_fetch_assoc($result5))
{
   if(condition)
       continue;
   $result6 = mysqli_query([...]);
}

Answer 2

你停止while循环中断; 您可以通过退出停止所有内容;

这段代码有什么意义？

Answer 3

您是否已尝试使用“break”？

例如，您可以按以下方式使用您的代码：

$result4 = mysqli_query($con,"SELECT no_of_vacancy FROM job_details WHERE jobscope= 'Information Technology' AND job_title='Oak 3 Films Pte Ltd (Sales Marketing Department)';");

$result5 = mysqli_query($con, "SELECT COUNT(company) FROM student_details WHERE jobscope1 = 'Information Technology' AND company = 'Oak 3 Films Pte Ltd (Sales Marketing Department)';");
while ($row5 = mysqli_fetch_assoc($result5))
{


$result6 = mysqli_query($con, "UPDATE `job_details` SET `no_of_vacancy`= `no_of_vacancy` - 2 WHERE `job_title` = 'Oak 3 Films Pte Ltd (Sales Marketing Department)';"));

if ($result6 == 0)
{
break;
}

我希望它可以提供帮助。

在计数器达到0之前停止循环

3 个答案: