Question

我有一个字符串列表，其中每个字符串基本上是从.csv程序中提取的一行数据。例如：

data[0] = '2014-01-31,46.83,48.55,46.80,48.03,3414400,48.03'

data[1] = '2014-01-30,47.47,48.11,47.29,48.00,2083900,48.00'

...等

我想将其转换为二维列表，以便：

newData[0][0] = '2014-01-31'
newData[0][0] = '2014-01-30'
newData[1][0] = '46.83'
newData[1][1] = '47.47'

...等

也就是说，我想在每个,分割字符串，但是当我尝试使用data.split(",")时，它不想这样做，因为它是一个列表。有什么想法吗？

Answer 1

对列表中的项目应用str.split：

newData = [item.split(',') for item in data]

<强>演示：

>>> data = ['2014-01-31,46.83,48.55,46.80,48.03,3414400,48.03', '2014-01-30,47.47,48.11,47.29,48.00,2083900,48.00']
>>> newData = [item.split(',') for item in data] 
>>> newData[0][0]
'2014-01-31'
>>> newData[1][0]
'2014-01-30'

正如其他人指出的那样，你应该使用csv模块来读取csv文件中的数据，考虑到该文件包含：

2014-01-31,46.83,48.55,46.80,48.03,3414400,48.03
2014-01-30,47.47,48.11,47.29,48.00,2083900,48.00

此代码将提供所需的输出：

import csv
with open('file.csv') as f:
    reader = csv.reader(f)
    data = list(reader)

将字符串列表转换为字符串数组

1 个答案: