Question

我有一个方法/函数，它传递了几个可能具有None值的变量。如何检查None值的所有变量并用尽可能最pythonic方式的字符串替换它？

示例代码：

def logData(self, var1=None, var2=None, var3=None):
    if var1 is None:
         var1 = "---"
    if var2 is None:
         var2 = "---"
    if var3 is None:
         var3 = "---"

    # what I would prefer / pseudo code:
    if list(var1, var2, var3) is None:
         list[1] = "---"

Answer 1

使用元组解包：

var1, var2, var3 = ['---' if (x is None) else x for x in (var1, var2, var3)]

Answer 2

var1, var2, var3 = (a or '---' for a in [var1, var2, var3])

Answer 3

您可以使用**kwargs：

来实现这一目标

def logData(self, **kwargs):
  for key,value in kwargs.iteritems():
    if value is None:
      # do assignment ...

检查条件是否与多个变量匹配

3 个答案: