@login_required重定向到下一个后面的Django

Question

我觉得这是一个简单的问题，我只是错过了一小步。

我想做以下任意数量（作为下一个参数中的术语）：

[not signed in] -> profile -> login?next=/accounts/profile/ -> auth -> profile.
[not signed in] -> newsfeed -> login?next=/newsfeed/` -> auth -> newsfeed.

我目前正在前往：

[not signed in] -> profile -> login?next=/accounts/profile/ -> auth -> loggedin
[not signed in] -> newsfeed -> login?next=/newsfeed/ -> auth -> loggedin

我希望以某种方式将next参数从login上的表单传递到auth并让auth重定向到此参数

目前我正在尝试login.html：

<input type='text' name="next" value="{{ next }}">

然而，这并没有获得下一个价值。我可以从调试工具栏中看到：

GET data
Variable    Value
u'next'     [u'/accounts/profile/']

views：

def auth_view(request):
  username = request.POST.get('username', '')
  password = request.POST.get('password', '')
  user = auth.authenticate(username=username, password=password)

  if user is not None:
    auth.login(request, user)
    print request.POST
    return HttpResponseRedirect(request.POST.get('next'),'/accounts/loggedin')
  else:
    return HttpResponseRedirect('/accounts/invalid')

login.html：

{% extends "base.html" %}

{% block content %}

  {% if form.errors %}
  <p class="error"> Sorry, you have entered an incorrect username or password</p>
  {% endif %}
  <form action="/accounts/auth/" method="post">{% csrf_token %}
    <label for="username">User name:</label>
    <input type="text" name="username" value="" id="username">

    <label for="password">Password:</label>
    <input type="password" name="password" value="" id="password">

    <input type='text' name="next" value="{{ request.GET.next }}">
    <input type="submit" value="login">
  </form>

{% endblock %}

settings：

from django.conf.urls import patterns, include, url

from django.contrib import admin
admin.autodiscover()

urlpatterns = patterns('',
    # Examples:

    url(r'^admin/', include(admin.site.urls)),
    ('^accounts/', include('userprofile.urls')),

    url(r'^accounts/login/$', 'django_yunite.views.login'),
    url(r'^accounts/auth/$', 'django_yunite.views.auth_view'),
    url(r'^accounts/logout/$', 'django_yunite.views.logout'),
    url(r'^accounts/loggedin/$', 'django_yunite.views.loggedin'),
    url(r'^accounts/invalid/$', 'django_yunite.views.invalid_login'),

)

settings：

# Build paths inside the project like this: os.path.join(BASE_DIR, ...)
import os
BASE_DIR = os.path.dirname(os.path.dirname(__file__))

# SECURITY WARNING: don't run with debug turned on in production!
DEBUG = True

TEMPLATE_DEBUG = True

ALLOWED_HOSTS = []


# Application definition

INSTALLED_APPS = (
    'django.contrib.admin',
    'django.contrib.auth',
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    'django.contrib.messages',
    'django.contrib.staticfiles',
    'debug_toolbar',
    'userprofile',
)

MIDDLEWARE_CLASSES = (
    'django.contrib.sessions.middleware.SessionMiddleware',
    'django.middleware.common.CommonMiddleware',
    'django.middleware.csrf.CsrfViewMiddleware',
    'django.contrib.auth.middleware.AuthenticationMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
    'django.middleware.clickjacking.XFrameOptionsMiddleware',
)

ROOT_URLCONF = 'django_yunite.urls'

WSGI_APPLICATION = 'django_yunite.wsgi.application'

# Internationalization
# https://docs.djangoproject.com/en/1.6/topics/i18n/

LANGUAGE_CODE = 'en-ca'

TIME_ZONE = 'EST'

USE_I18N = True

USE_L10N = True

USE_TZ = True


# Static files (CSS, JavaScript, Images)
# https://docs.djangoproject.com/en/1.6/howto/static-files/

STATIC_URL = '/static/'

STATICFILES_DIRS = (
    ('assets', '/home/user/GitHub/venv_yunite/django_yunite/static/'),
    )

TEMPLATE_DIRS = (
    './templates',
    '/article/templates',
)

STATIC_ROOT = "/home/user/Documents/static/"

AUTH_PROFILE_MODULE = 'userprofile.UserProfile'

打印陈述显示空u'next'

Answer 1

查询字符串隐式传递给任何视图，无需编写任何特殊代码。

您所要做的就是确保next密钥从实际登录表单（在您的情况下，这是在/accounts/login/中呈现的表单）传递给{{ 1}}查看。

为此，您需要确保在设置中启用了请求模板上下文处理器（/accounts/auth）。要执行此操作，首先需要导入django.core.context_processors.request的默认值，然后在TEMPLATE_CONTEXT_PROCESSORS中将请求处理器添加到其中，如下所示：

settings.py

然后是以下形式：

from django.conf import global_settings

TEMPLATE_CONTEXT_PROCESSORS = global_settings.TEMPLATE_CONTEXT_PROCESSORS + (
    "django.core.context_processors.request",
) 

现在，在<form method="POST" action="/accounts/auth"> {% csrf_token %} <input type="hidden" name="next" value="{{ request.GET.next }}" /> {{ login_form }} <input type="submit"> </form> 视图中：

/accounts/auth

Answer 2

您要找的是login decorator。

在 views.py

中

from django.contrib.auth.decorators import login_required

@login_required(login_url="/accounts/login/")
def profile( request ):
   """your view code here"""
   return HttpResponse("boo ya", "text/html")

然后在 urls.py 中添加身份验证网址

(r'^accounts/login/$', 'django.contrib.auth.views.login'),

最后：确保已安装的应用中安装了django.contrib.auth，并安装了AuthenticationMiddleware。

<强> settings.py

INSTALLED_APPS = (
   -- snip --,
   'django.contrib.auth',
   )


MIDDLEWARE_CLASSES = (
   -- snip --,
   'django.contrib.auth.middleware.AuthenticationMiddleware',
   )

templates / registration / login.html

<form method="POST" action="/accounts/login/">
   {% csrf_token %}
   <input type="hidden" name="next" value="{{ next }}" />
   {{ login_form }}
   <input type="submit">
</form>

Answer 3

某个时候面临类似的情况。为了解决这个问题，我写了自己的装饰师 -

def validate_request_for_login(f):
    def wrap(request):
        if not request.user.is_authenticated():
            return redirect("/login?next=" + request.path)
        return f(request)
    return wrap

以上装饰器检查用户身份验证。如果用户未经过身份验证，则通过从请求对象传递url将用户重定向到登录页面。

Answer 4

我最终做的是以下内容。对我来说，这似乎是一个黑客工作。有没有更好的方法来使用csrf登录？

views：

def login(request):
  c={}
  c.update(csrf(request))
  if 'next' in request.GET:
    c['next'] = request.GET.get('next')
  return render_to_response('login.html', c)

def auth_view(request):
  username = request.POST.get('username', '')
  password = request.POST.get('password', '')
  user = auth.authenticate(username=username, password=password)

  if user is not None:
    auth.login(request, user)

    if request.POST.get('next') != '':
      return HttpResponseRedirect(request.POST.get('next'))
    else:
      return HttpResponseRedirect('/accounts/loggedin')
  else:
    return HttpResponseRedirect('/accounts/invalid')

login.html：

<input type="hidden" name="next" value="{{ next }}"/>

Answer 5

def login_user(request):
    if request.method=='POST':
        print(request.POST,request.GET.get('next'))
        username=request.POST['email']
        password=request.POST['password']
        user = authenticate(request,username=username,password=password)
        if user:
            login(request,user)
        else:
            print('user not found')
            messages.error(request,'Invalid Credentials')
            return render(request, "login.html")
        return redirect(request.GET.get('next','/'))
    return render(request, "login.html")