我有这个问题:
SELECT MODELLI.MOD_DESC,
COUNT(MOD_DESC)
FROM VEGA.DISTRIB AS DISTRIB,
VEGA.MODELLI AS MODELLI
WHERE DISTRIB.DIS_FLAG = 'M'
AND DISTRIB.DIS_MOD = MODELLI.MOD_COD
GROUP BY MODELLI.MOD_DESC
但我也希望在MODELLI.MOD_DESC上有ORDER BY。
我怎么能这样做?
感谢。
答案 0 :(得分:2)
尝试,
SELECT MODELLI.MOD_DESC, COUNT(MODELLI.MOD_DESC)
FROM VEGA.DISTRIB DISTRIB, VEGA.MODELLI MODELLI
WHERE DISTRIB.DIS_FLAG = 'M' AND DISTRIB.DIS_MOD = MODELLI.MOD_COD
GROUP BY MODELLI.MOD_DESC ORDER BY MODELLI.MOD_DESC
它会像OP建议的那样工作..
立即尝试..
答案 1 :(得分:2)
您可以在ORDER BY
子句之后使用GROUP BY
子句,例如
SELECT MODELLI.MOD_DESC,
COUNT(MOD_DESC)
FROM VEGA.DISTRIB DISTRIB,
VEGA.MODELLI MODELLI
WHERE DISTRIB.DIS_FLAG = 'M'
AND DISTRIB.DIS_MOD = MODELLI.MOD_COD
GROUP BY MODELLI.MOD_DESC
ORDER BY MODELLI.MOD_DESC;
答案 2 :(得分:1)
SELECT MODELLI.MOD_DESC, COUNT(MOD_DESC)
FROM VEGA.DISTRIB AS DISTRIB, VEGA.MODELLI AS MODELLI
WHERE DISTRIB.DIS_FLAG = 'M' AND DISTRIB.DIS_MOD = MODELLI.MOD_COD
GROUP BY MODELLI.MOD_DESC
order by MODELLI.MOD_DESC ASC