Question

我在这里找到了一个解决方案How to flip an individual UIView (without flipping the parent view)

但似乎这对我不起作用。在Interface Builder中，我已经使用uiview设置了所有内容，并在两个uiviews内部，大小相同，第一个视图显示在顶部，我为这3个视图创建了三个出口。

在viewDidLoad中：

 [self.view addSubview:self.contentView]
 [self.contentView addSubview:firstView]
 [self.contentView addSubview:secondView]

我有一个uigesture。当用户点击屏幕时，IBAction执行翻转：

-(IBAction)flip:(id *)sender
{
 if(faceUp){

       // execute transition from firstview to second
 }else{

      //execute transition from secondview to first
 }

 faceUp = !faceUp;
}

这项工作完全是我第一次点击并翻转从第一次到第二次，然后如果我再次点击翻转开始然后它没有任何结束，视图消失并保持容器视图显示什么，因为它的颜色是设置清除。我怎么解决这个问题？

这是带有轻击手势方法和三个插座的控制器：

  #import "ContactViewController.h"
  #import "InfoContactView.h"
  #import "ImageLogoView.h"

  @interface ContactViewController ()
  @property (strong, nonatomic) IBOutlet InfoContactView *contactInfoView;
  @property (strong, nonatomic) IBOutlet ImageLogoView *imageLogoView;
  @property (nonatomic) BOOL faceUp;
  @property (strong, nonatomic) IBOutlet UIView *parentView;


  @end

 @implementation ContactViewController

 - (id)initWithNibName:(NSString *)nibNameOrNil bundle:(NSBundle *)nibBundleOrNil
 {
  self = [super initWithNibName:nibNameOrNil bundle:nibBundleOrNil];
  if (self) {
    // Custom initialization
  }
 return self;
 }

- (void)viewDidLoad
{
  [super viewDidLoad];
 // Do any additional setup after loading the view.

  self.parentView.backgroundColor =[UIColor clearColor];
  [self.view addSubview:self.parentView];
  [self.parentView addSubview:self.contactInfoView];
    [self.parentView addSubview:self.imageLogoView];


    self.faceUp = NO;
 }

- (void)didReceiveMemoryWarning
{
     [super didReceiveMemoryWarning];
   // Dispose of any resources that can be recreated.
}


-(void)setFaceUp:(BOOL)faceUp
{
    _faceUp = faceUp;

}

-(void)setParentView:(UIView *)parentView
{
    _parentView =parentView;
}

-(void)setContactInfoView:(InfoContactView *)contactInfoView
{
 _contactInfoView = contactInfoView;
}

-(void)setImageLogoView:(ImageLogoView *)imageLogoView
{
  _imageLogoView = imageLogoView;
}

- (IBAction)showInfo:(UITapGestureRecognizer *)sender {




  if (self.faceUp == NO) {
      [UIView transitionFromView:self.imageLogoView toView:self.contactInfoView
                        duration:1.5
                         options:UIViewAnimationOptionTransitionFlipFromLeft
                      completion:NULL];
      NSLog(@"Pass from logo to info : imageLogoView = %@",self.imageLogoView.description);

      NSLog(@"dettagli = %@",self.contactInfoView);



  }
   else if(self.faceUp == YES){
      [UIView transitionFromView:self.contactInfoView toView:self.imageLogoView
                        duration:1.5
                         options:UIViewAnimationOptionTransitionFlipFromRight
                      completion:NULL];

      NSLog(@"Pass from info to logo: imageLogoView = %@",self.imageLogoView.description);

      NSLog(@"dettagli = %@",self.contactInfoView);

  }

  self.faceUp = !self.faceUp;

 }




 @end

Answer 1

我试图在Xcode中重建你的问题。我在每次转换之前和之后添加了一些代码行来记录parentView的子视图。从日志中判断，您的初始视图的框架（self.imageLogoView）在某个时刻重置为宽度和高度为0：

<UIView: 0x8b84310; frame = (159.5 284.5; 0 0); autoresize = W+H; layer = <CALayer: 0x8b84370>>

这意味着它仍然存在但你却看不到它。

显然 Autolayout负责调整视图框架的大小。如果您为View Controller停用Autolayout，则转换工作正常。（要取消激活Autolayout，请在故事板中选择相应的View Controller。在右栏（实用工具）转到第一个选项卡 first tab 并取消选中“Use Autolayout”。）

另一方面，Autolayout被认为是一件好事，或者至少它被Apple推广。因此，如果您希望使用Autolayout，您必须通过添加适当的约束来自己处理视图的框架。首先选择您的imageLogoView并通过选中相应的框添加宽度和高度的约束，如下面的屏幕截图所示。然后对您的contactInfoView执行相同操作。

Screenshot Xcode Constraints

这应该可以解决问题。

翻转两个子视图不能连续工作

1 个答案: