如何从php调用python脚本

时间:2014-02-18 20:14:45

标签: php python csv python-2.x

我需要将值从PHP传递给Python脚本,然后将该值写入csv文件。但是,我遇到了困难,我的python在调用时写了一个空的csv文件。可能是什么问题。

<?php
if (isset($_POST['data'])){
  $data = $_POST['data'];
  $result = exec("python processData.py .$data");
  echo $result;
  }                
 ?>

和processData.py

import nltk
from nltk.corpus import stopwords
from nltk import stem
import re   
import sys
import csv

mysentence = sys.argv[1]
f = open("output.csv", "wb")
tokens = nltk.word_tokenize(mysentence)
d = [i.lower() for i in tokens if (not tokens in stopwords.words('english'))]    
porter = nltk.PorterStemmer()
for t in tokens:
    result = porter.stem(t)    
    f.write(result+"\n")
    print result
f.close()

3 个答案:

答案 0 :(得分:1)

$result = exec("python processData.py .$data");
输入时可能会出现

问题:$data = "hello little world"; 它会传递给

 $result = exec("python processData.py .hello little world");

sys.argv将是

  ["processData.py",".hello","little","world"]

不幸的是,我不确定nltk将如何处理,但肯定不会像你想要的那样

作为旁白

d = [i.lower() for i in tokens if (not tokens in stopwords.words('english'))]  

应该重写

if  tokens not in stopwords.words('english'):
   d = [i.lower() for i in tokens]
else: #if your actually planning on using d anywhere ... currently your just throwing it out
      # not using d makes all of this just as effective as a pass statement
   d = []

答案 1 :(得分:0)

在$ data之前可能是,试试这个:

$result = exec("python processData.py {$data}");

问候!

答案 2 :(得分:0)

exec()或其他任何内容都没有问题。问题是nltk模块无法找到nltk_data目录。对于它,只需找到系统中nltk_data所在的位置:通常为~/nltk_data。现在导入在运行该函数时添加该路径。

import nltk;

现在,nltk.data.path是搜索模块的位置列表。你可以这样做:

nltk.data.path.append("your location/directory");
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