Question

我的代码正在为第一个输入工作，但现在我想重新提示用户输入并重复该过程，直到用户输入'stop'。我已经尝试将我的代码放在另一个while循环中，创建一个不同的函数定义并将代码放在现有的if语句中。这是我目前的代码：

def findInfo(myList, target):
    list.sort(myList)
    #print myList, target
    guesses = 0
    low = 0
    high = len(myList)-1
    mid = (high + low) / 2
    while high >= low:
        if target == myList[mid][0]:
            print "Here are your results:"
            print 'state:', myList[mid][0]
            print 'total number:', myList[mid][1]
            print '% passed:', myList[mid][2]
            print '% female students:', myList[mid][3]
            return True            
        elif target > myList[mid][0]:
            low = mid + 1
            guesses += 1
            print "guess", guesses
        elif target < myList[mid][0]:
            high = mid - 1
            guesses += 1
            print "guess", guesses
        mid = (high + low)/ 2
    print False, "no match found"
    return False

我真的很困惑在哪里放置代码重新询问用户输入，直到输入的某个单词。

Answer 1

你可以使用cmd lib，类似的东西：

import cmd


class myApp(cmd.Cmd):

    def do_findInfo(self,target, myList = defaultList):
        list.sort(myList)
        #print myList, target
        guesses = 0
        low = 0
        high = len(myList)-1
        mid = (high + low) / 2
        while high >= low:
            if target == myList[mid][0]:
                print "Here are your results:"
                print 'state:', myList[mid][0]
                print 'total number:', myList[mid][1]
                print '% passed:', myList[mid][2]
                print '% female students:', myList[mid][3]
                return True            
            elif target > myList[mid][0]:
                low = mid + 1
                guesses += 1
                print "guess", guesses
            elif target < myList[mid][0]:
                high = mid - 1
                guesses += 1
                print "guess", guesses
            mid = (high + low)/ 2
        print False, "no match found"
        return False   

        def do_EOF(self, line):
            return True

if __name__ == '__main__':
    myApp().cmdloop()

这将显示您需要输入的命令行：“findInfo target”

Answer 2

为什么不简单地做某事。像这样：

def term(s):
    return s in ['stop', 'exit', 'quit']

if __name__=='__main__':
    inp = ''
    while not term(inp):
        inp = raw_input('prompt: ')
        if not term(inp):
            try:
                i = int(inp)
                print(findInfo(myList, i))
            except ValueError as e:
                print('Invalid input: {}'.format(e.message))

python不断提示用户输入，直到输入某个单词

2 个答案: