Question

我有生成JSON字符串的代码。该代码生成的示例字符串如下所示。我已通过JSON lint工具对其进行了验证，并且验证完美。

{"ShipToName" : "(    ) CARPINTERIA         CA", "ShipToAddress1" : "3785 SANTA CLAUS LANE", "ShipToAddress2" : "", "ShipToCity" : "CARPINTERIA", "ShipToState" : "CA", "ShipToZip" : "93013", "ShipVia" : "UPS", "Terms" : "01", "SalesRep" : "KV1" }

然后我有一些JQuery将解析该字符串。现在我只是想提醒字符串的一个部分，以确保代码正常工作。我尝试了以下两种方法但没有成功：

尝试＃1：提醒'未定义'

function hidShipTo_IndexChanged(sender, args) {
                var strComboID = $find("<%=rcbCustomer.ClientID%>");
                var strValue = strComboID.get_value();
                var strShipToVal = $("#hidShipTo").val();
                var strData = "{ strSoldToSelected: '" + strValue + "', strShipToSelected: '" + strShipToVal + "' }";
                alert("yes");
                $.ajax({
                    type: "POST",
                    url: "/webservices/ProductServer.asmx/PopulateShipToDetails",
                    data: strData,
                    contentType: "application/json; character=utf-8",
                    dataType: "json",
                    success: function (msg) {
                        alert(msg.SalesRep);
                    },
                    failure: function (xhr, ajaxoptions, thrownError) {
                        alert("Error1:" + xhr.status);
                        alert("Error2:" + thrownError);
                    }
                });
            }

尝试＃2：在JQuery库对象中抛出错误

function hidShipTo_IndexChanged(sender, args) {
                var strComboID = $find("<%=rcbCustomer.ClientID%>");
                var strValue = strComboID.get_value();
                var strShipToVal = $("#hidShipTo").val();
                var strData = "{ strSoldToSelected: '" + strValue + "', strShipToSelected: '" + strShipToVal + "' }";
                alert("yes");
                $.ajax({
                    type: "POST",
                    url: "/webservices/ProductServer.asmx/PopulateShipToDetails",
                    data: strData,
                    contentType: "application/json; character=utf-8",
                    dataType: "json",
                    success: function (msg) {
                        alert(msg.SalesRep);
                    },
                    failure: function (xhr, ajaxoptions, thrownError) {
                        alert("Error1:" + xhr.status);
                        alert("Error2:" + thrownError);
                    }
                });
            }

关于如何访问JSON字符串中的每个项目的任何想法？

谢谢！

Answer 1

因为你的代码没有抛出一个未定义的异常，所以我们可以推断'msg'并不是未定义的。

使用调试器查看你的msg真正包含的内容：

alert(msg.SalesRep);
console.log(msg);

注意：contentType应为'charset = utf-8'，而不是'character = utf-8'。你发送的字符串也是无效的json。它应该是双引号而不是单引号。

Answer 2

所以，一旦我检查了控制台日志，答案就非常简单了。我添加了这行代码，我能够开始访问JSON字符串中的所有内容：

var obj = $.parseJSON(msg.d);

Answer 3

这没有任何意义：

var strData = "{ strSoldToSelected: '" + strValue + "', strShipToSelected: '" + strShipToVal + "' }";

应该只是

var strData = { strSoldToSelected: strValue, strShipToSelected: strShipToVal };

解析用于AJAX成功调用的JSON字符串

3 个答案: