Question

我希望按周和日分组数据。说我想找（Januray所有星期日的音量总和）+（2月所有星期日的音量总和）+ ...我做的就像是

  select CONVERT(VARCHAR(10),date,111),
         DATENAME(weekday,date) as Weekday,
         DATEPART(month,date) as Month,
         DATEPART(year,date) as year,
         sum(volume)
    from traffic_data_replica
group by CONVERT(VARCHAR(10),date,111),
         DATENAME(weekday,date),
         DATEPART(month,date),
         DATEPART(year,date)
order by DATEPART(year,date),
         CONVERT(VARCHAR(10),date,111),
         DATEPART(month,date),
         DATENAME(weekday,date) ;

但这不是我想要的理想结果:(

Answer 1

您在组中包含实际日期（CONVERT(VARCHAR(10),date,111)），因此日期是汇总级别。尝试这样的事情：

SELECT Year(date), 
       Month(date), 
       Datename(weekday, date) AS Weekday, 
       Sum(volume) 
FROM   traffic_data_replica 
GROUP  BY Year(date), 
          Month(date), 
          Datename(weekday, date) 
ORDER  BY Year(date), 
          Month(date), 
          Datename(weekday, date);

您可以使用datepart()代替year()和month()。我发现后者更容易阅读和输入。

按工作日和月分组

1 个答案: