Question

我有两个数组

names = ["name1", "name2"]
tracks = ["track1", "track2"]

我正在尝试将两个数组合并为一个新数组

data => ["name1 track1", "name2 track2"]

我尝试了以下

1)   @data = @name.zip(@tracks)flatten 
     produces ["name1", "track1", "name2", "track2"]

2)   @data = @name.at(0).concat(@tracks.at(0)) + @name.at(1).concat(@tracks.at(1))
     produces ["name1track1name2track2"]

3)   @name.each do |n|
      @tracks.each do |t|
       @data.push n + " " + t
       end
     end
     produces ["name1 track1", "name1 track2", "name2 track1", "name2 track2"]

我似乎无法解决这个问题。我将不胜感激。

Answer 1

names  = ["name1", "name2"] #note the "="
tracks = ["track1", "track2"]

p names.zip(tracks).map{|e| e.join(" ")}
#=> ["name1 track1", "name2 track2"]

Answer 2

你可以这样做：

data = []
names.each_with_index {|x,y| data << "#{x} #{tracks[y]}" }
data # => ["name1 track1", "name2 track2"]

Answer 3

names.map {|name| "#{name} #{tracks[names.index(name)]}"}
=> ["name1 track1", "name2 track2"]

Answer 4

这是一个巧妙的方法：

names = ["name1", "name2"]
tracks = ["track1", "track2"]

names.zip(tracks).map { |a| a.join(" ") }
# => ["name1 track1", "name2 track2"]

首先，

names.zip(tracks)

给我们

[["name1", "track1"], ["name2", "track2"]]

然后我们使用map

将内部数组与空格连接起来

Answer 5

我喜欢product方法

=> array_size = names.size
=> names.product(tracks).
     each_with_index.
     map { |x,i| x.join(" ") if (i % array_size - i / array_size).zero? }.compact
=> ["name1 track1", "name2 track2"]

Answer 6

另：

names.map { |s| s << ' ' << tracks.shift }
  #=> ["name1 track1", "name2 track2"]

如果无法修改names（和/或tracks），则必须对副本进行操作。

变体：

[].tap { |a| names.size.times {a << (names.shift + ' ' + tracks.shift) } }

Answer 7

有点不同的方式：

names  = ["name1", "name2"] 
tracks = ["track1", "track2"]

names.each_index.map { |i| "#{names[i]} #{tracks[i]}" }
# => ["name1 track1", "name2 track2"]

Answer 8

另一种方式，与@ steenslag非常相似（我有时讨厌打开块:-)）

names = ["name1", "name2", "name3"]
tracks = ["track1", "track2", "track3"]

names.zip([' '] * names.length, tracks).map(&:join)
=> ["name1 track1", "name2 track2", "name3 track3"]

组合来自两个单独数组的字符串元素

8 个答案: