Question

我正在尝试实现自定义bradcastreciever。但是当我注册它时，我的意图返回null。我不知道这里出了什么问题？

我的活动就在这里

private MyReciever mReceiver;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    this.mReceiver = new MyReciever();
    Intent result=registerReceiver(this.mReceiver, new IntentFilter(
            "com.example.Broadcast"));
    int status = result.getIntExtra("HighScore",0);
    System.out.println(status+"  Yahoo");
    setContentView(R.layout.activity_main);
    for (int i = 0; i < 10; i++) {

        try {               
            if (i == 7) {
                // MyReciever mr=new MyReciever();
                    Intent intent = new intent();               
                intent.setAction("com.example.Broadcast");
                intent.putExtra("HighScore", 1000);
                sendStickyBroadcast(intent);
                break;

            }
        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

}

@Override
protected void onStop() {
    // TODO Auto-generated method stub
    super.onStop();
    unregisterReceiver(mReceiver);
}

和Reciever是

     public class MyReciever extends BroadcastReceiver{

    @Override
    public void onReceive(Context context, Intent intent) {
        // TODO Auto-generated method stub

        //int data= intent.getIntExtra("HighScore",0);
        Toast.makeText(context, "Highest Score", Toast.LENGTH_LONG).show();
    }

}

我已获得android mainfest文件的许可

     <uses-permission android:name="android.permission.BROADCAST_STICKY"/>

Answer 1

它将返回null，因为在您拨打registerReceiver()时，尚未为该操作广播任何内容。

Answer 2

在清单文件中声明您的接收器

<receiver
        android:name=".MyReceiver"

    </receiver>

SendBroadcast无法正常工作

2 个答案: