如何使用Java保持TCP连接?

时间:2014-02-22 16:56:02

标签: java sockets tcp

我想做的是:

1)创建一个TCP套接字,侦听本地计算机中的特定端口号。 (服务器)

2)创建另一个TCP套接字,它将连接到我创建的第一个TCP套接字。(客户端)

3)通过客户端向服务器发送一些数据。

4)客户从服务器接收数据。

5)不要关闭连接..等一会儿..

6)从服务器接收更多数据。

这是我的代码:

public class MyTCPServer {

    public static void main(String argv[]) throws Exception {
        String clientSentence;
        String capitalizedSentence;
        ServerSocket welcomeSocket = new ServerSocket(6789);
        while (true) {
            Socket connectionSocket = welcomeSocket.accept();
            BufferedReader inFromClient = new BufferedReader(new InputStreamReader(connectionSocket.getInputStream()));
            DataOutputStream outToClient = new DataOutputStream(connectionSocket.getOutputStream());
            clientSentence = inFromClient.readLine();
            System.out.println("Received: " + clientSentence);
            capitalizedSentence = clientSentence.toUpperCase() + '\n';
            outToClient.writeBytes(capitalizedSentence);
            outToClient.writeBytes(String.valueOf(System.currentTimeMillis()));
            Thread.sleep(1000);
            outToClient.writeBytes(String.valueOf(System.currentTimeMillis()));
        }
    }

}

因此,此TCP套接字侦听端口6789.请注意,它从客户端发送回收到的字符串,对其进行大写并将其返回。然后服务器发送currentTimeMillis,等待1000毫秒,然后再次发送timeMillis。

这是我的客户:

public class MyTCPClient {

    public static void main(String[] args) throws Exception {
        String sentence;
        String modifiedSentence;
        BufferedReader inFromUser = new BufferedReader(new InputStreamReader(System.in));
        Socket clientSocket = new Socket("localhost", 6789);
        DataOutputStream outToServer = new DataOutputStream(clientSocket.getOutputStream());
        BufferedReader inFromServer = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
        sentence = inFromUser.readLine();
        outToServer.writeBytes(sentence + '\n');
        modifiedSentence = inFromServer.readLine();
        System.out.println("FROM SERVER: " + modifiedSentence);
    }

}  

然而,当我测试我的代码时,我得到了:

Received: asdf
Exception in thread "main" java.net.SocketException: Connection reset by peer: socket write error
    at java.net.SocketOutputStream.socketWrite0(Native Method)
    at java.net.SocketOutputStream.socketWrite(SocketOutputStream.java:92)
    at java.net.SocketOutputStream.write(SocketOutputStream.java:115)
    at java.io.DataOutputStream.writeBytes(DataOutputStream.java:259)
    at MyTCPServer.main(MyTCPServer.java:28)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
    at java.lang.reflect.Method.invoke(Method.java:597)
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120)

如何在客户端保持连接活动?此外,我希望能够从客户端发送更多文本。

2 个答案:

答案 0 :(得分:4)

最简单的方法是在客户端代码中放置一个循环。像这样:

   while ((modifiedSentence = inFromServer.readLine()) != null) {
       System.out.println("FROM SERVER: " + modifiedSentence);
       sentence = inFromUser.readLine();
       outToServer.writeBytes(sentence + '\n');
   }

readLine()方法在等待来自服务器的消息时阻塞,因此客户端不会退出。

请参阅下面有关如何编写套接字服务器和客户端的简单教程:

http://docs.oracle.com/javase/tutorial/networking/sockets/clientServer.html

答案 1 :(得分:0)

您的客户退出。它不会尝试“保持连接活动”。您的服务器将数据写入客户端未读取的客户端。所以它得到它应该得到的异常。如果您想避免异常,请添加缺少的读数。