Question

我正在尝试使用PHP将CSV文件上传到我数据库中的现有表中。

这是我的完整代码：

<?php
include("detail.php");


 $connect = mysql_connect("$host", $user, $password) or die("Couldn't connect to SQL  Server on $myServer");
 mysql_select_db("$database") or die("Couldn't open database $myDB");

 if (mysqli_connect_errno())
 {
 echo "Failed to connect to MySQL: " . mysql_connect_error();
 }


 define('CSV_PATH','E:/4th Year/FYP/'); // specify CSV file path

  $csv_file = CSV_PATH . "Cash2011.csv"; // Name of your CSV file
 $csvfile = fopen($csv_file, 'r');
 $theData = fgets($csvfile);
 $i = 0;
 while (!feof($csvfile))
 {
   $csv_data[] = fgets($csvfile, 1024);
   $csv_array = explode(",", $csv_data[$i]);
   $insert_csv = array();
   $insert_csv['cashAmount'] = $csv_array[0];
   $insert_csv['cashReceivedDate'] = $csv_array[1];
   $insert_csv['customerID'] = $csv_array[2];
   $insert_csv['invoiceNo'] = $csv_array[3];
   $insert_csv['monthNum'] = $csv_array[4];
   $insert_csv['yearNum'] = $csv_array[5];
   $query = "INSERT INTO cash2011(cashAmount,cashReceivedDate,invoiceNo,monthNum,yearNum) VALUES ('','".$insert_csv['cashAmount']."','".$insert_csv['cashReceivedDate']."','".$insert_csv['customerID']."','".$insert_csv['invoiceNo']."','".$insert_csv['monthNum']."','".$insert_csv['yearNum']."')";
   $n=mysql_query($query, $connect);
   $i++;
   }
   fclose($csvfile);
   echo "File data successfully imported to database!!";
   ?>

这些是我不断收到的错误：未定义的偏移量：第47行的C：\ Apache2.2 \ htdocs \ clearTables.php中的1（$ insert_csv ['cashAmount'] = $ csv_array [0];）。未定义的偏移量：第48行的C：\ Apache2.2 \ htdocs \ clearTables.php中的2。

有谁知道问题是什么？感谢

Answer 1

我测试了你的代码，工作得很好...... 并且，当我回显查询时，返回：

    INSERT INTO cash2011(cashAmount,cashReceivedDate,invoiceNo,monthNum,yearNum) 
VALUES ('','ad4213','ad4214','ad4215','ad4216','adware','ad7777 ')
    //'','ad4213','ad4214','ad4215','ad4216','adware','ad7777 ' -> data in my example csv file

一些事情...... 我相信你的文件不存在，这就是为什么你有这些错误，试着在while (!feof($file))之前检查这一行

 if(is_file($csv_file)){ //your code}

另外，在您的查询中，您有5个值，而行定义中只有4个值。而且，为什么你有,？

如果您的问题仍然存在，请查看我的回答here，如果您查看，则与您的代码类似。

Answer 2

以下代码中存在语法错误。所以替换

$query = "INSERT INTO cash2011(cashAmount,cashReceivedDate,invoiceNo,monthNum,yearNum) VALUES ('','".$insert_csv['cashAmount']."','".$insert_csv['cashReceivedDate']."','".$insert_csv['customerID']."','".$insert_csv['invoiceNo']."','".$insert_csv['monthNum']."','".$insert_csv['yearNum']."')";

通过

$query = "INSERT INTO cash2011(cashAmount,cashReceivedDate,invoiceNo,monthNum,yearNum) VALUES ('".$insert_csv['cashAmount']."','".$insert_csv['cashReceivedDate']."','".$insert_csv['customerID']."','".$insert_csv['invoiceNo']."','".$insert_csv['monthNum']."','".$insert_csv['yearNum']."')";

使用PHP将CSV文件上载到数据库时出错

2 个答案: