Question

我试图让while循环运行dur次，但是当我运行它只是坐在那里，我假设计算，似乎永远。这是一个简单的脚本，不需要很长时间才能运行，因此我假设我已经弄乱了while循环。

这是代码： #Compound兴趣计算器

print "Enter amounts without $, years or %"
loan = input("How many dollars is your loan? ")
dur = input("How many years is your loan for? ")
per = input("What percent is the interest on your loan? ")
percent = per / 100
count = 0

#First calculation of amount
first = loan * percent
count = count + 1

#Continued calculation occurs until count is equal to the duration set by the user
while count <= dur:
    out = first * percent

#Prints output
output = out + loan
print str(output)

Answer 1

您的代码存在许多问题。

percent始终为0，因为您使用的是整数除法。请改为percent = per / 100.0。
正如其他人所说，你必须增加count来结束循环。
在循环中不更改first和percent，out的计算值在循环的每次迭代中都是相同的。请改为first = first * percent。

最后，你根本不需要循环。就这样做：

output = loan * (1 + per/100.)**dur

Answer 2

您需要在while循环中增加count，否则停止条件（count <= dur）将永远不会发生。

while count <= dur:
    # do something
    count += 1

如果您事先知道要做某事的次数，您也可以使用：

for i in xrange(dur): # use range if python3
   # do something

另请注意，您的代码还有另一个问题：您并未真正计算复合兴趣。在每一步中，您都需要重新计算first * percent，而不是将percent添加到之前的兴趣中。你应该这样做：

# First calculation of amount
out = loan * percent
count = count + 1

while count <= dur:
    out *= (1.0 + percent)
    count += 1

Answer 3

count永远不会在循环中发生变化。这样做

while count <= dur:
    out = first * percent
    count += 1

Python - 获取while循环运行一定次数

3 个答案: