Question

我正在创建一个包含很多项的ListView，ListView的每一行都包含一个TextView和一个“删除”按钮，当单击“删除”按钮（而不是单击该行）时，该行应显示toast，运行动画并从列表中删除但它只显示吐司（当我点击该行时效果很好）

这是我的代码

import java.util.ArrayList;
import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.view.animation.Animation;
import android.view.animation.Animation.AnimationListener;
import android.view.animation.AnimationUtils;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.ListView;
import android.widget.TextView;
import android.widget.Toast;

public class MainActivity extends Activity {
    String[] items = new String[20];
    ListView lv;
    MyAdapter mAdapter;
    ArrayList<String> data = new ArrayList<String>();
    private int position;
    Animation ani;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        for (int i = 0; i < 20; i++) {
            items[i] = String.valueOf(i + 1);
            data.add(items[i]);
        }

        lv = (ListView) findViewById(R.id.listView1);
        mAdapter = new MyAdapter(getApplication(), R.layout.custom_row, data);
        lv.setAdapter(mAdapter);
        ani = AnimationUtils.loadAnimation(getApplicationContext(), R.animator.fadeout);
        lv.setOnItemClickListener(new OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> arg0, View arg1, final int arg2, long arg3) {
                Toast.makeText(getApplicationContext(), "You have clicked on item " + arg2, Toast.LENGTH_SHORT).show();
                arg1.startAnimation(ani);
                ani.setAnimationListener(new AnimationListener() {
                    @Override
                    public void onAnimationStart(Animation animation) {
                    }

                    @Override
                    public void onAnimationRepeat(Animation animation) {
                    }

                    @Override
                    public void onAnimationEnd(Animation animation) {
                        mAdapter.remove(arg2);
                    }
                });
            }
        });
    }

    class MyAdapter extends ArrayAdapter<String> {

        ArrayList<String> data;

        @Override
        public View getView(int position, View convertView, ViewGroup parent) {
            LayoutInflater inflater = getLayoutInflater();
            View v = inflater.inflate(layout, parent, false);
            TextView tv = (TextView) v.findViewById(R.id.textView1);
            tv.setText(data.get(position));
            Button bt = (Button) v.findViewById(R.id.button1);
            bt.setOnClickListener(new MyClick(this, position));
            return v;
        }

        class MyClick implements View.OnClickListener {
            MyAdapter p;
            int i;

            public MyClick(MyAdapter parent, int pos) {
                p = parent;
                i = pos;
            }

            @Override
            public void onClick(View v) {
                lv.performItemClick(lv.getAdapter().getView(i, null, null), i, i);
            }
        }

        public void remove(int pos) {
            data.remove(pos);
            notifyDataSetChanged();
        }

        int layout;

        public MyAdapter(Context c, int l, ArrayList<String> data_name) {
            super(c, l, data_name);
            layout = l;
            data = data_name;
        }
    }
}

提前感谢您的帮助。

Answer 1

修改onClick类中的MyClick回调方法，如下所示：

@Override
public void onClick(View v) {
    lv.performItemClick(lv.getChildAt(i), i, i);
}

由于p.getView(i, null, null)会使item中不属于ListView的新视图曝光，因此您应使用lv.getChildAt(i)获取实际item。

performItemClick不会启动动画

1 个答案: